What is the correct answer?

Anyone? i need help asap plzzz i’ll mark you as brainlist and like it

Solnce55 [7]

Answer:

x = 50°

Step-by-step explanation:

Recall that for a triangle, the exterior angle is equal to the sum of its two remove interior angles (also see attached for reference).

in our case, the exterior angle is given as 105° and its two remote interior angles are x and 55°

therefore

105° = 55° + x

x = 105° - 55°

x = 50°

4 0

3 years ago

Read 2 more answers

57. What number is 25% of 32?

horrorfan [7]

57. 8
58. 8
59. 24
60. 11.25 or 11
61. 20.52 or 21
62. 144
63. 7.37 or 7
64. 50%
65. 25%
66. 10%
67. 20%
68. 25%

hope this helped :)

5 0

3 years ago

A shooting star forms a right triangle with the Earth and the Sun, as shown below:

frez [133]

The positions of the sun, earth and shooting star form a right angled triangle, where distance between earth and sun is 'y', and the angle 'x°' is given

Now, in a right angled triangle using trigonometry, we can determine a side of the triangle is one of the sides and one of the angles is known

Here, if we use cos x = $\frac{Base}{Hypotenuse}$ we can determine the distance between the shooting star and the sun. This can be done because we know that the base is 'y', the angle is x° and the hypotenuse represents the distance between the sun and the shooting star

Note: cos values for each x are definite.

3 0

3 years ago

Irma works for a service that delivers groceries and pet supplies. She earns a base monthly salary of $1,900. In addition, she g

ruslelena [56]

Irma’s annual income has the delivery fees already taken out. earnings based on salary and commission is higher becuase fees have not been taken out

3 0

2 years ago

Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Anit [1.1K]

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\$

$\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to c= - \frac{1}{2}$

put the value of c in equation (i):

$\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\$

put the value of d in equation (iv):

$\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

4 0

3 years ago