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2 years ago

Simplify the expression: √4x^2/3y

Mathematics

2 answers:

777dan777 [17]2 years ago

3 0

I think it’s 2x^1/3y hope this helped

NeX [460]2 years ago

3 0

Answer:

$\frac{2x}{3y}$

please give me brainliest!

Step-by-step explanation:

$\frac{\sqrt{4x^2}}{3y} = \frac{2x}{3y}$

I'm assuming that the entire 4x^2 term is under the radical sign. If it isn't, then

$\frac{\sqrt{4}x^2}{3y} = \frac{2x^2}{3y}$

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3 years ago

Find a function that models the area A of an equilateral triangle in terms of the length x of one of its sides.

creativ13 [48]

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4 years ago

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3 years ago

Y=4(1/3)^x growth or decay and why ?

PtichkaEL [24]

Answer:

Decay

Step-by-step explanation:

The equation shown has a ratio(number raised to the power) less than 1, so therefore it is decay. This basically comes from the fact that if you raise a number less than 1 to a power, it become smaller than the number itself.

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3 years ago

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

3 0

3 years ago