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Law Incorporation [45]
3 years ago
7

An algebra tile configuration. 2 tiles are in the Factor 1 spot: 1 is labeled + x and 1 is labeled +. 1t ile is in the Factor 2

spot: it is labeled + x. 2 tiles are in the Product spot: 1 is labeled + x squared and 1 is labeled + x.
What is the product of x(x + 1)?

2x + x
x2 + 2x
2x2 + x
x2 + x
Mathematics
1 answer:
Nadusha1986 [10]3 years ago
4 0
The answer is D (x^2 +x)
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BartSMP [9]

Use the power rule (which says to multiply the exponents)

1) n⁴ˣ⁸ = n³²

2) x³ˣ⁻⁵ = x⁻¹⁵ = \frac{1}{x^{15} }

3) c³ˣ⁵ * d³ˣ⁰ = c¹⁵ * d⁰ = c¹⁵ * 1 = c¹⁵

8 0
3 years ago
I need some help with this:)I'll apreciate the answers.
Travka [436]
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7 0
3 years ago
The student council hires a dj to play music at the school dance. They pay DJ Dan for 3.5 h at his hourly rate plus a 125$ setup
fiasKO [112]
3.5h + 125 = 405
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6 0
3 years ago
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The postal service charges $2 to ship packages up to 5 ounces in weight and $0.20 for each additional ounce up to 20 ounces. Aft
Luda [366]

Answer:

The domain is all of the x values. From the graph, all of the x values are greater than or equal to 0 so the answer is x ≥ 0.

3 0
3 years ago
Marquise has 200200200 meters of fencing to build a rectangular garden.
Lera25 [3.4K]

Answer:

2500 Square meters

Step-by-step explanation:

Given the garden area (as a function of its width) as:

A(w)=-w^2+100w

The maximum possible area occurs when we maximize the area. To do this, we take the derivative, set it equal to zero and solve for w.

A'(w)=-2w+100

-2w+100=0

-2w=-100

w=50 meters

Since Marquise has 200 meters of fencing to build a rectangular garden,

Perimeter of the proposed garden=200 meters

Perimeter=2(l+w)

2(l+50)=200

2l+100=200

2l=200-100=100

l=50 meters

The dimensions that will yield the maximum area are therefore:

Length =50 meters

Width=50 meters

Maximum Area Possible =50 X 50 =<u>2500 square meters.</u>

3 0
3 years ago
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