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Ronch [10]
3 years ago
8

54 ÷ 6 x (12-4) + 2 =​

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

3

Step-by-step explanation:

1. 54÷6 =9

2. (12-4)=8

3. 9-8 = 1

4. 1+2 = 3

5. I hope this helps it's pretty simple oh and 3 is your anansw.Also you can you your calculator

Stolb23 [73]3 years ago
3 0

Answer:

a=72\frac{2}{3}

Step-by-step explanation:

56/6*(12-4)+2=n

56/6*8+2-2=n-2

56/6*8/8=(n-2)/8

x=9\frac{1}{3}

x=(n-2)/8

y=74\frac{2}{3}

y=n-2=a

a=72\frac{2}{3}

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a rectangle is 4 times as long as it wide. if the length is increased by 4 inches and the width is decreased by 1 inch, the area
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What value for x makes the equation 4x + 9 = 3(x – 2) + 10 true?
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A 2-kg object is fired from a cannon at a 30º angle wrt to the horizontal. the initial speed is 35 m/s. how high will the object
kompoz [17]
     <span> You have :
----------------

v0 = 35 m/s

B = angle of elevation = 30 deg

a suby = - g

v suby0 = ( v0 ) ( sin B )

v suby0 = ( 35 m/s ) ( sin 30 ) = 17.5 m/s

At maximum height :
------------------------------

v suby = vy* = 0.0

t = t*

y = ymax = y*

Basic kinematics gives :
-------------------------------------

a suby = dv suby / dt = -g ------> dt = dv suby /a suby

v suby = dy/dt ------> dt = dy / vsuby

dt = dv suby / a suby = dy / v suby

( v suby ) ( d v suby) = ( a suby ) dy = ( -g ) dy

Now integrate and get :
-----------------------------------

( v suby* )^2 - ( v suby0)^2 ( 1/2 ) = ( -g ) ( ymax )

ymax = [ ( v suby0 )^2 - ( v suby* )^2 ] / [ ( 2 ) ( g ) ]

ymax = ( 17.5 m/s )^2 - ( 0.0 m/s )^2 ] / [ ( 2 ) ( 9.807 m/s^2 ) ]

ymax = 15.6 m <------------------

Check the result:
--------------------------

t* = v suby0 / g = ( 17.5 m/s ) / ( 9.807 m/s^2 ) = 1.784 s

y* - y0 = ( v suby0 ) ( t* ) - ( g/2 ) ( t* )^2

y* = ( 17.5 m/s ) ( 1.784 s ) - ( 9.807 m/s^2 / 2 ) ( 1.784 s )^2

y* = ymax = 31.23 m - 15.61 m = 15.6 m

The ymax values agree.</span>
6 0
3 years ago
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