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slega [8]
3 years ago
10

Out of 1200 students of a school only 85% passed. how many students failed?​

Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:15

Step-by-step explanation:

If 85% pass then 15% failed and 15% of 1,200 is 180 so 180 people failed.

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What is the interquartile range of 77 88 92 81 86 84 86 83 and how do you get it thx plz help
puteri [66]
To find the IQR you first need to write it in numerical order

77, 81, 83, 84, 86, 86, 88, 92


IQR is just Q3 - Q1

Q1 is the middle of the first have, since it has an even set of 4 numbers in the first half you need to take the average of the two middle ones.. which is 82

Q3 done the same process would be 87. 

87 - 82 = 5

IQR = 5
6 0
3 years ago
Y is directly proportional to x when y=30, x=6
rosijanka [135]

Answer:

a) y = 5x

b) y = 60

Step-by-step explanation:

Since, y is directly proportional to x when y=30, x=6

\therefore \:  y \:  \alpha \:  \: x \\ \therefore \:  y =  kx ...(1) \\ plug \: y = 30 \: and \: x = 6  \: in \: eq \: (1)\\ 30 = k \times 6 \\ k =  \frac{30}{6}  \\ k = 5 \\ plug \: k = 5 \: in \: (1) \\ y = 5x....(2) \: (required \: equation) \\ plug \: x = 12 \: in \: eq \: (2) \\ y = 5 \times 12 \\  \huge \red{ \boxed{y = 60}}

4 0
2 years ago
Write an equation in slope-intercept form (0,2) (7,-1)
maksim [4K]

Answer:

y=-3/7x+2

Step-by-step explanation:

first formula (Slope): y2-y1/x2-x1

-1-2/7-0= -3/7

second formula (point slope): y-y1=m(x-x1)

y-2=-3/7(x-0)

(distribute the -3/7)

y-2=-3/7x-0

(add 2 to both sides)

y=-3/7x+2

6 0
3 years ago
What are the solutions to the quadratic equation 98-x2=0
kifflom [539]

98-x^2=0\qquad\text{add}\ x^2\ \text{to both sides}\\\\98=x^2\to x^2=98\\\\x=\pm\sqrt{98}\\\\x=\pm\sqrt{49\cdot2}\\\\x=\pm\sqrt{49}\cdot\sqrt2\\\\\boxed{x=-7\sqrt2\ \vee\ x=7\sqrt2}

8 0
3 years ago
Select the correct location in the expression.
kogti [31]

Answer:

78

Correct term:60

Step-by-step explanation:

We are given that

\frac{4x^4-6x^3+6x+3}{x-3}

The quotient of this expression is given by

4x^3+6x^2+18x+78+\frac{183}{x-3}

We have to find the term in this expression  which contains an error.

\frac{4x^4-6x^3+6x+3}{x-3}

The quotient of this expression is given by

=4x^3+6x^2+18x+60

Dividend=Divisor\times quotient+ remainder

Using the formula

4x^4-6x^3+6x+3=(x-3)(4x^3+6x^2+18x+60)+\frac{183}{x-3}

We can see that in the given expression there is 60 in place of 78.

The error in the expression of quotient is 78.

Correct term is 60.

4 0
2 years ago
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