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3 years ago

10

Please help me please please please help please help please help please help please help please help please help please help ple

ase help

2 answers:

DedPeter [7]3 years ago

5 0

Answer:

its between c or b

Step-by-step explanation:

I've done this test before

maks197457 [2]3 years ago

3 0

Answer:

B

Step-by-step explanation:

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Translate each algebraic expression or equation into a verbal phrase 9y <br>

rosijanka [135]

Answer: just multiply 9 and y together: 9 x y

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3 years ago

Joe claims that 1/4 is of a figure is less than 1/8 of the same figure. Which statement is true?

Rainbow [258]

Answer:

I disagree with joe.

Step-by-step explanation:

1/8 of a figure is smaller than 1/4. 2/8 of a figure is the same thing as 1/4 though.

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3 years ago

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3 years ago

WILL GIVE BRAINLIEST! PLZ HELP ASAP! <br> What is the order of operations for 4.8 x 2 + 3.2?

KatRina [158]

Answer:

12.8

Step-by-step explanation:

Here multiplication is done before addition.

Given

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7 0

3 years ago

Read 2 more answers

prove that the quadrilateral whose vertices are the points A(-1,1), B(-3,4), C(1,5) and D(3,2) is a parallelogram.

Vsevolod [243]

Answer:

Since $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ , then the quadrilateral ABCD is a parallelogram.

Step-by-step explanation:

First, we label each point of the quadrilateral with the help of a graphing tool. If the quadrilateral ABCD is a parallelogram, then $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ . If we know that $A(x,y) =(-1, 1)$ , $B(x,y) =(-3,4)$ , $C(x,y) = (1,5)$ and $D(x,y) = (3,2)$ , then the measure of each vector is, respectively:

$\overrightarrow{AB} = (-3,4)-(-1,1)$

$\overrightarrow{AB} = (-2, 3)$

$\overrightarrow{DC} = (1,5)-(3,2)$

$\overrightarrow{DC} = ( -2,3)$

$\overrightarrow{AD} = (3,2)-(-1,1)$

$\overrightarrow{AD} = (4, 1)$

$\overrightarrow{BC} = (1,5)-(-3,4)$

$\overrightarrow{BC} = (4, 1)$

Since $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ , then the quadrilateral ABCD is a parallelogram.

7 0

3 years ago