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3 years ago

182-y=226 solve for y

Mathematics

2 answers:

weqwewe [10]3 years ago

7 0

Step-by-step explanation:

-y=226-182

-y=44

Y=-44

antiseptic1488 [7]3 years ago

5 0

Answer:

$182 - y = 226 \\ 182 - ( - 44) = 226$

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Scores on a college entrance examination are normally distributed with a mean of 500 and a standard deviation of 100. What perce

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Answer:

The percentage is $P(350 < X 650 ) = 86.6\%$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 500$

The standard deviation is $\sigma = 100$

The percent of people who write this exam obtain scores between 350 and 650

$P(350 < X 650 ) = P(\frac{ 350 - 500}{ 100}$

Generally

$\frac{X - \mu }{\sigma } = Z (The \ standardized \ value \ of \ X )$

$P(350 < X 650 ) = P(\frac{ 350 - 500}{ 100}$

$P(350 < X 650 ) = P(-1.5$

$P(350 < X 650 ) = P(Z < 1.5) - P(Z < -1.5)$

From the z-table $P(Z < -1.5 ) = 0.066807$

and $P(Z < 1.5 ) = 0.93319$

=> $P(350 < X 650 ) = 0.93319 - 0.066807$

=> $P(350 < X 650 ) = 0.866$

Therefore the percentage is $P(350 < X 650 ) = 86.6\%$

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3 years ago

WHAT IS GREATEST WHOLE NUMBER THAT ROUNDS TO 277,300

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4 years ago

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1) $x^{2} +2x-10=0$
a=1
b=2
c=-10
$x= \frac{-(2) +or- \sqrt{ 2^{2}+4(1)(-10) } }{2(1)}$
$x= \frac{-2 + or - \sqrt{4+40} }{2}$
$x= \frac{-2 +or- \sqrt{44} }{2}$
$x= \frac{-2+or- 2\sqrt{11} }{2}$
$x= -1+or- \sqrt{11}$
$\sqrt{11}=3.32$
-1+3.32 = 2.32
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2) $x^{2} -2x-9=0
$
a=1
b=-2
c=-9
$x= \frac{-(-2)+or- \sqrt{ (-2)^{2}+4(1)(-9) } }{2(1)}$
$x= \frac{2+or- \sqrt{4+36} }{2}$
$x= \frac{2+or- \sqrt{40} }{2}$
$x= \frac{2+or-2 \sqrt{10} }{2}$
$x=1+or- \sqrt{10}$
$\sqrt{10} =3.16$
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3) $x^{2} -9x+5=0$
a=1
b=-9
c=5
$x= \frac{-(-9)+or- \sqrt{(-9)^{2}-4(1)(5) } }{2}$
$x= \frac{9+or- \sqrt{81-20} }{2}$
$x= \frac{9+or- \sqrt{61} }{2}$
$x= \frac{9}{2} +or- \frac{ \sqrt{61} }{2}$
$\sqrt{61} = 7.81$
$\frac{7.81}{2} =3.91$
$\frac{9}{2}=4.5$
4.5+3.91 = 8.41
4.5-3.91 = 0.59

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4 years ago