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3 years ago

10. Choose all fractions equivalent to 36/40 A) 3/4 B) 9/10 C) 9/40 D) 18/20

Mathematics

2 answers:

Talja [164]3 years ago

5 0

Answer:

B, D

Step-by-step explanation:

36/40 simplified is 9/10

9/10 x 2 = 18/20

I hope this helps!

Zarrin [17]3 years ago

4 0

B) 9/10
9 times 4 =36
10times4 =40

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Which choice is equivalent to the quotient shown here for acceptable values of x?

OleMash [197]

Sqrt(5x) * Sqrt(x) + 3
= 5^(1/2) * x^(1/2) * x^(1/2) + 3
= 5^(1/2) *x +3
=5^(1/2)*x^(2/2) +3
=Sqrt(5*x^2) +2

So the answer is A

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3 years ago

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What is the slope of y=-1/3x+4the slope of y=-1/3x+4

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Answer:

-1/3

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept

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3 years ago

Gas in Germany cost 1.50 euros per liter. how much is this in dollars per gallon

SIZIF [17.4K]

To solve this problem, you will have to first find how many US Dollars are in 1 Euro. Upon looking this up, I see that currently 1 Euro is worth 1.23 US Dollars. Next, you must calculate how many liters are in a gallon. Looking this up shows that 1 liter is equal to 0.264 gallons.

Since 0.264 is not a whole gallon and we are asked to find the price per gallon, we should next calculate how many liters can fit in a gallon. To do this, we will divide 1 by 0.264, which gives us 3.78. This tells us that 3.78 liters will fit into a gallon.

The cost of 1L of gas in euros is 1.50 Euros. Since we need 3.78L to equal 1 gallon, we can calculate the cost of this to be:

3.78 * 1.50 = €5.67

Earlier we determined that 1 euro is worth 1.23 US Dollars. Our final step is to convert our €5.67 per gallon to dollars per gallon. To do this, we simply have to multiply 5.67 by 1.23. This gives us $6.97.

So, our answer is that the cost is $6.97 per gallon.

Hopefully this is correct and makes sense to you. This is how I would approach the question.

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3 years ago

High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers

Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

Step:-1

Given that the mean of the Population = 540HP

Given that the size of the sample 'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

Step(ii):-

Degrees of freedom = n-1 =9-1 =8

t₀.₀₀₅ = 3.3554

The 99% of a confidence interval for the average maximum HP for the experimental engine.

$(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2} + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )$

$(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )$

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

Final answer :-

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

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3 years ago

B) Find the value of a^2 + b^2 when a = 3 and b= -2

Zielflug [23.3K]

Answer:

Step-by-step explanation:

a = 3

b = -2

a² + b² = 3² + (-2)²

= 9 + 4

= 13

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3 years ago

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