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skad [1K]
3 years ago
6

10. Choose all fractions equivalent to 36/40 A) 3/4 B) 9/10 C) 9/40 D) 18/20

Mathematics
2 answers:
Talja [164]3 years ago
5 0

Answer:

B, D

Step-by-step explanation:

36/40 simplified is 9/10

9/10 x 2  = 18/20

I hope this helps!

Zarrin [17]3 years ago
4 0
B) 9/10
9 times 4 =36
10times4 =40
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If y varies directly as x and y = 21 when x = 5, find x when y = 42.
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Answer: 10

<u>Step-by-step explanation:</u>

varies directly means: \frac{y}{x} = k

Step 1: solve for k   ⇒  \frac{21}{5} = k

Step 2: plug in the given value and k to solve for the missing value: \frac{42}{x} = \frac{21}{5}

42(5) = 21(x)

\frac{42(5)}{21} = \frac{21(x)}{21}

2(5) = x

10  = x


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3 years ago
What is negative 1 and three fifths divided by negative two thirds equals?
Rudik [331]
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3 years ago
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topjm [15]
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3 years ago
Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0
Leokris [45]

Substitute v(x)=-2x+y(x), so that \dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}. Then the ODE is equivalent to

\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7

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\dfrac{\mathrm dv}{v^2-9}=\mathrm dx

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\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)

so that integrating both sides is trivial and we get

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\dfrac{v-3}{v+3}=Ce^{6x}

\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}

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y=2x+\dfrac6{1-Ce^{6x}}-3

Given the initial condition y(0)=0, we find

0=\dfrac6{1-C}-3\implies C=-1

so that the ODE has the particular solution,

\boxed{y=2x+\dfrac6{1+e^{6x}}-3}

5 0
3 years ago
Mitch is attending a 4-year college. As a freshman, he was approved for a 10-year, federal
stich3 [128]

Answer:

Interest capitalization occurs when unpaid interest is added to the principal amount of your student loan. When the interest on your federal student loan is not paid as it accrues (during periods when you are responsible for paying the interest), your lender may capitalize the unpaid interest.

Step-by-step explanation:

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