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kaheart [24]
3 years ago
12

X^2-4x+3=0 solutions larger and smaller solutions ​

Mathematics
1 answer:
andrew11 [14]3 years ago
5 0

Answer:

x = 3 or x = 1

Step-by-step explanation:

Solve for x over the real numbers:

x^2 - 4 x + 3 = 0

Subtract 3 from both sides:

x^2 - 4 x = -3

Add 4 to both sides:

x^2 - 4 x + 4 = 1

Write the left hand side as a square:

(x - 2)^2 = 1

Take the square root of both sides:

x - 2 = 1 or x - 2 = -1

Add 2 to both sides:

x = 3 or x - 2 = -1

Add 2 to both sides:

Answer: x = 3 or x = 1

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If the value of x is 3, then what is the value of 2-8x+4x+4
Veronika [31]
Hey there,
2 - 8x + 4x + 4
2 - 8(3) + 4(3) + 4
2 - 24 + 12 + 4
-6

Hope this helps :))

<em>~Top♥</em>
5 0
3 years ago
Anybody know the answer?
marysya [2.9K]
I'd start by writing an equation for each of the right triangles. (Pythagorean theorem)

y² + 9² = z²
x² + z² = (4+9)²
4² + y² = x²

we want to find z so combine the equations by substituting the other variables x,y out.

substitute y² for (x² - 4²) in 1st equation.

(x² - 4²) + 9² = z²

now by rearranging the 2nd equation we can substitute x² for (13² - z²)

(13² - z²) - 4² + 9² = z²
169 - z² - 16 + 81 = z²
234 - z² = z²
234 = 2z²
234/2 = z²
117 = z²
√(117) = z
√(9*13) = z
3√(13) = z

13 goes in the box




































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