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Verizon [17]
3 years ago
8

the line defined by the equation y=-(4/7)x+5 is prependicular to the line defined by which equation ? (1) y=(4/7)x+3 (2) y=-(4/7

)x+3 (3) y=-(7/4)x+3 (4) (7/4)x+3
Mathematics
1 answer:
lesantik [10]3 years ago
3 0
Y=mx+b
m=slope

perpendicular lines have slopes that multiply to -1

the line we have is y=-4/7x+5
therefor
if the slope we are looking for is m
(-4/7)m=-1
times -7/4 both sides
m=7/4
we are looking for
y=7/4x+b


last one is answer  
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Step-by-step explanation:

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7 0
3 years ago
Solve for the value of c. ​
Ipatiy [6.2K]

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7 0
3 years ago
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snow_lady [41]

Answer:

$2000 was invested at 5% and $5000 was invested at 8%.

Step-by-step explanation:

Assuming the interest is simple interest.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned.
  • P = principal invested.
  • r = interest rate (in decimal form).
  • t = time (in years).

Given:

  • Total P = $7000
  • P₁ = principal invested at 5%
  • P₂ = principal invested at 8%
  • Total interest = $500
  • r₁ = 5% = 0.05
  • r₂ = 8% = 0.08
  • t = 1 year

Create two equations from the given information:

\textsf{Equation 1}: \quad \sf P_1+P_2=7000

\textsf{Equation 2}: \quad \sf P_1r_1t+P_2r_2t=I\implies 0.05P_1+0.08P_2=500

Rewrite Equation 1 to make P₁ the subject:

\implies \sf P_1=7000-P_2

Substitute this into Equation 2 and solve for P₂:

\implies \sf 0.05(7000-P_2)+0.08P_2=500

\implies \sf 350-0.05P_2+0.08P_2=500

\implies \sf 0.03P_2=150

\implies \sf P_2=\dfrac{150}{0.03}

\implies \sf P_2=5000

Substitute the found value of P₂ into Equation 1 and solve for P₁:

\implies \sf P_1+5000=7000

\implies \sf P_1=7000-5000

\implies \sf P_1 = 2000

$2000 was invested at 5% and $5000 was invested at 8%.

Learn more about simple interest here:

brainly.com/question/27743947

brainly.com/question/28350785

5 0
1 year ago
If f(x)= 3x + 10x and g(x)=5x - 3 find (f+g)(x)
Illusion [34]

Answer:

18x-3

Step-by-step explanation:

f(x)= 3x + 10x

g(x)=5x - 3

f(x)+g(x) = 3x + 10x + 5x - 3

Combine like terms

             = 18x -3

6 0
3 years ago
The corporate team-building event will cost $14 if it has 7 attendees. If there are 9
kobusy [5.1K]

Answer: for 9 attendees it would cost $18

Step-by-step explanation: First you have to find the unit rate. So for every 7 attendees it costs $14, divide them both by the GCF which is 7. 14÷7=2

7÷7=1

So for every 1 attendee it is $2.

Now to figure out how much it would cost for 9 attendees, figure out what you have to do to 1 to get 9. Multiply it by 9.

And whatever you do to one number you have to do for the other. So $2 • 9 = $18

So for every 9 attendees it costs $18.

5 0
3 years ago
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