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Verizon [17]
3 years ago
8

the line defined by the equation y=-(4/7)x+5 is prependicular to the line defined by which equation ? (1) y=(4/7)x+3 (2) y=-(4/7

)x+3 (3) y=-(7/4)x+3 (4) (7/4)x+3
Mathematics
1 answer:
lesantik [10]3 years ago
3 0
Y=mx+b
m=slope

perpendicular lines have slopes that multiply to -1

the line we have is y=-4/7x+5
therefor
if the slope we are looking for is m
(-4/7)m=-1
times -7/4 both sides
m=7/4
we are looking for
y=7/4x+b


last one is answer  
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10 seconds

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Elliot finishes the race in 1/2 of 20 sec or 10 sec

4 0
2 years ago
5 2/3 gave to her 4 friends how much did each one receive
Olin [163]

Answer:

Let's see what to do buddy...

Step-by-step explanation:

If it is 5 + 2/3

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Step (1)

First we have to find all she has :

5 \frac{2}{3} = 5 +  \frac{2}{3} =  \frac{5 \times 3}{3} +  \frac{2}{3} = \\   \frac{15}{3} +  \frac{2}{3} =  \frac{17}{3}

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Step (2)

To find how much did each of them receive , we must divided all by the number of her friends which is 4.

So we have :

\frac{17}{3} \div 4 =  \frac{17}{3} \times  \frac{1}{4} =  \frac{17}{12} \\

So each of her friends receive 17/12 .

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If it is 5 × 2/3

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Step (1)

Firs we have to find all she has :

5 \times  \frac{2}{3} =  \frac{10}{3} \\

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Step (2)

To find how much did each of them receive , we must divided all by the number of her friends which is 4.

So we have :

\frac{10}{3} \div 4 =  \frac{10}{3} \times  \frac{1}{4} =  \frac{10}{12} \\

So each of her friends receive 10/12 .

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And we're done.

Thanks for watching buddy good luck.

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4 0
3 years ago
Use compatible numbers to estimate the quotient. 635÷9
gayaneshka [121]
Here, 635/9
Nearest divisible of 9 is 630 so, 
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In short, Your Quotient would be 70

Hope this helps!
6 0
3 years ago
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Nola will make B. $ 3, 224 in one year.

5 0
3 years ago
2. John earns a 3% commission for every car he sells. Today he sold a car for $13,600. How much commission did he receive? (To f
OlgaM077 [116]

Answer:

$408

Step-by-step explanation:

Find 3% of $13,600:

3 * 13,600 / 100 = $408

7 0
3 years ago
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