Question

A handbag contains seven coins and three

Answer 1

Answer:

0.59998

Step-by-step explanation:

Number of keys = 3

Number of coins = 7

Total = 10

Number of items taken out = 2

Expected number of keys taken out:

Let x = Number of keys taken out

X = 0

1st pick = 7/10

2nd pick = 6/9

7/10 * 6/9 = 0.46666

X = 1

(7/10 * 3/9) + (3/10 * 7/9) = 0.46666

X = 2

(3/10 * 2/9) = 0.066666

X : ____ 0 ______ 1 _______ 2

P(X): _0.46666__0.46666 _0.06666

Expected value :

(0*0.46666) + (1*0.46666) + (2*0.06666)

= 0.59998