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german
3 years ago
5

Can somebody help me out with this Algebra 2 work? If you could that'd be really appreciated!! Good luck!

Mathematics
1 answer:
larisa [96]3 years ago
6 0

Answer:

8 OR -8 OR Both

Step-by-step explanation:

-2 x 4 = -8

-8 x -8 x -8 = -64

Square root = 8 OR -8

1 to the 9th power = 1

-8 / 1 = -8

8/1 = 8

Hope that helps!

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A. 125

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  • Solution of equation ( x ) = <u>7</u>

Step-by-step explanation:

In this question we have given with an equation that is <u>4</u><u> </u><u>(</u><u> </u><u>5</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>(</u><u> </u><u>9</u><u>x</u><u> </u><u>+</u><u> </u><u>3 </u><u>)</u><u>.</u> And we are asked to solve this equation that means we have to find the value of <u>x</u><u>.</u><u> </u>

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<u>\quad \longrightarrow \: 4 ( 5x - 2 ) = 2 ( 9x + 3 )</u>

<u>Step </u><u>1</u><u> </u><u>:</u> Removing parenthesis :

\quad \longrightarrow \:20x - 8 = 18x + 6

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 8 from both sides :

\quad \longrightarrow \:20x - \cancel{ 8 }+  \cancel{8} = 18x + 6 + 8

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\quad \longrightarrow \:20x = 18x + 14

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\quad \longrightarrow \:20x - 18x =  \cancel{18x }+ 14 -  \cancel{18}

On further calculations we get :

\quad \longrightarrow \:2x = 14

<u>Step </u><u>4</u><u> </u><u>:</u> Dividing with 2 on both sides :

\quad \longrightarrow \: \frac{ \cancel{ 2}x}{ \cancel{2}}  =   \cancel{\frac{14}{2} }

On further calculations we get :

\quad \longrightarrow \:  \blue{\boxed{ \frak{x = 7}}}

  • <u>Therefore</u><u>,</u><u> </u><u>solution</u><u> </u><u>of </u><u>this </u><u>equation</u><u> </u><u>is </u><u>7</u><u> </u><u>or </u><u>we </u><u>can </u><u>say </u><u>that </u><u>value </u><u>of </u><u>this </u><u>equation</u><u> </u><u>is </u><u>7</u><u> </u><u>.</u>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

We are verifying our answer by substituting value of x in given equation. So ,

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  • L.H.S = R.H.S

  • Hence, Verified.

<u>Therefore</u><u>,</u><u> </u><u>our </u><u>value</u><u> for</u><u> x</u><u> is</u><u> </u><u>correct </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
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