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-BARSIC- [3]
3 years ago
5

Bob says that he can find the area of the triangle below using the formula: A =

%7B2%7D" id="TexFormula1" title="\frac{1}{2}" alt="\frac{1}{2}" align="absmiddle" class="latex-formula"> * 8 *18 * sin (120°). Is he correct? Explain why or why not.

Mathematics
1 answer:
Goryan [66]3 years ago
8 0

Answer:

No.

Step-by-step explanation:

No, Bob is not correct.

The formula he's using is the following:

A=\frac{1}{2} ab\sin(C)

The important thing here is that the angle is between the two sides.

In the given triangle, 120 is not between 8 and 18. Therefore, using this formula will not be valid.

Either Bob needs to find the other side first or find the angle between 8 and 18.

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MARKING BRAINLIEST !!
soldi70 [24.7K]

answers

4) opposite sides are parallel

1) opposite angles are equal

5) all are quadrilateral

property's of a parallelogram

1)sum \: of \: angeles \: = 180 \\ 2)opposite \: sides \: are \: cogruent \\ 3)opposite \: angles \: are \: congruent \\ 4)cosecutive \: angles \: are \: supplymentary \\ 5)diaganols \: bisect \: \\ thnk \: you[/tex]

7 0
3 years ago
Study the solutions of three equations on the right. Then complete the statements below.
Hoochie [10]

Answer:

Part 1) There are two real solutions

Part 2) There is one real solution

Part 3) There are no real solutions

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

If the radicand is positive

(b^{2}-4ac) >0  ------> There are two real solutions

If the radicand is zero

(b^{2}-4ac) =0  ------> There is one real solution

If the radicand is negative

(b^{2}-4ac)  ------> There are no real solutions

therefore

Part 1) The radicand is positive

so

There are two real solutions

Part 2) The radicand is equal to zero

so

There is one real solution

Part 3) The radicand is negative

so

There are no real solutions

7 0
3 years ago
Read 2 more answers
What is the quotient of -8a^8b^-2/10a^-4b^-10 in simplified form? Assume a=0 b=0 A.) -4a^12b^8/5 B.)-4a^32b^5/5 C.)a^12b^8/80 D.
Naily [24]

-8a^8b^-2/10a^-4b^-10

= (-8/10) a^(8+4)b^(-2+10)

= -4/5 a^12 b^8

=-4 a^12 b^8 / 5

Answer is A.) -4 a^12 b^8 / 5

4 0
3 years ago
Read 2 more answers
In how many ways can 50 cards be chosen from a standard deck of 52 cards using permutations
kumpel [21]
Permutation of 50 is 50! or 50*49*48*47*46.... and so on. I doubt they actually want you to find out what 50*49*48... is, so I'd just put 50!
8 0
3 years ago
Which of the following has a value of 84? <br> A. 512 <br> B. 4,096 <br> C. 32 <br> D. 83
andreev551 [17]
Answer is B. 4,096

I encountered this problem before. This is a trick question.
84 is not really the number 84. It is 8 raised to the 4th power.

So 8⁴ is equal to 4,096.

8 x 8 x 8 x 8 = 4,096

    8 x 8 =      64
  64 x 8 =    512
512 x 8 = 4,096




6 0
4 years ago
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