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galina1969 [7]
2 years ago
10

If one factor of x2 2x â€" 24 is (x 6), what is the other factor? (x 8) (xâ€"8) (x 4) (xâ’4).

Mathematics
1 answer:
FrozenT [24]2 years ago
4 0

The correct question is; x² + 2x - 24

The other factor of <em>x² </em><em>+</em><em> </em><em>2x </em><em>-</em><em> 24</em> asides (x+6) is; (x-4)

The expression given can be factorised as follows;

  • x² + 6x -4x - 24

  • x(x+6) -4(x+6)

  • (x+6) (x-4).

Consequently, the other factor of the expression is (x-4).

Read more on quadratic factors;

brainly.com/question/14718354

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| 2(4+6) = how do I solve this?​
podryga [215]

Answer:

20

Step-by-step explanation:

You use the distributive property.

Distribute the 2 to whatever is inside the parentheses. (You will multiply)

4×2=8

2×6=12

Substitute the answers above into the parentheses.

(8+12)=20

7 0
3 years ago
What is 8% of 75?.?.?
alisha [4.7K]

Answer:

6

Step-by-step explanation:

(8:100) * 75

(8*75) : 100

600:100 = 6

4 0
3 years ago
What should be done to both sides of the equation in order to solve y + 8.5 = 17.2?
Amanda [17]

Answer:

Subtract 8.5

Step-by-step explanation:

To solve the equation, y has to be isolated (only y will be on one side of the equation)

To do this, we have to get rid of the 8.5, so it has to be subtracted from both sides.

So, the correct answer is subtract 8.5

7 0
3 years ago
Read 2 more answers
Please help me answer these 2 questions with a FULL explanation so I know how to do the rest myself. Giving brainliest.
sveticcg [70]

Answer to 1:

\frac{x^3}{2y^25}

First thing you want to do is combine like terms on the bottom. Since it's multiplication, all you have to do is add the exponents. So for x you'd get x raised to the -9 power and for y you'd get 2y raised to the power of 7

Second thing is the numerator of the fraction. Since this is raising what is inside the paranthesis to a power, you must multiply this power by the powers of x and y, respectively. You should get x raised to the power of -6 and y raised to the power of -18

Here's where it gets complicated. to rationalize the problem, you must add parts from the numerator and denominator or vice versa. You cannot have any negative exponents anywhere in the fraction.  So that means for x you have to add 9 to the x on the top to cancel out the -6 and rationalize the remaining x's. You should end up with x^3.

For y, you work the opposite way. Since the negatives are only on the top, you simply add 18 to the bottom y's and it remains rationalized.

If done correctly this should come out to x^3/2y^25

Answer to 2:

(x^20y^12)/256

First thing you can do on this one is to cancel out the x^0s. Anything to the power of 0 equals one so only the coefficients will remain. Multiply those together and you'll get 4.

Next you will rationalize the ys. Add the bottom 3 to the top to cancel out the denominator and you're left with y^-3. Leave it like this for now.

Now is the difficult part. You must take everything that is inside the parenthesis to the power of -4. That includes the coefficients and the exponents. 4^-4 = 1/256. This means that you now must move the coefficients to the bottom. You should currently have y^-3/(256x^5).

Now take the exponents to the power using the same rules as question 1. -3*-4 = 12 and 5*-4 = -20. You should now have y^12/(256x^-20)

Lastly, we must rationalize the denominator. To do so, move the x^-20 to the numerator and make the exponent positive. After doing this, you have the answer: (x^20y^12)/256

3 0
2 years ago
Subtract 3/y-2 - 1/y+3
Helen [10]
To subtract fractions, we need a common denominator.

\frac{3}{y-2} - \frac{1}{y+3}

the common denominator will be (y-2)(y+3)

\frac{3(y+3)-1(y-2)}{(y-2)(y+3)}
\frac{3y + 9 - y + 2}{(y-2)(y+3)}
\frac{2y + 11}{(y-2)(y+3)}

The answer above will be the simplified form.
3 0
3 years ago
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