Solve 4y^2+7y+2=0 to 2 decimal places
1 answer:
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Answer:
Option c
Step-by-step explanation:
given that limit x tending to 4 of the function (3x-4) is 8
This implies for all values of x such that for epsilon >0 arbitrary small ,
, we get
|f(x)-8|<3epsilon
this is equivalent to the option c.
Proof:
Consider
Hence it follows that option C is right.
Answer:
Option C. No solution is the right answer.
Step-by-step explanation:
Here the given equations are y = x²+2x+3 -----(1)
and y = 4x-2 -------(2)
Now we substitute the value of y from equation 2 into 1.
x²+2x+3 = 4x-2
x²+2x+3-2x = 4x-2-2x
x²+3 = 2x-2
x²+3-2x = 2x-2x-2
x²-2x+3 = -2
x²-2x+5 = 0
Then value of
Since in this solution √(-20) is not defined. Therefore there is no solution.