All categories

2 years ago

Please help me out with this

Mathematics

1 answer:

Anna [14]2 years ago

6 0

Answer:

$\frac{9}{64}$ π in²

Step-by-step explanation:

The area (A) of the circle is calculated using the formula

A = πr² ← r is the radius

here the diameter = $\frac{3}{4}$

and radius is half the diameter, hence

r = $\frac{3}{8}$ , so

A = π × ( $\frac{3}{8}$ )² = $\frac{9}{64}$ π in²

You might be interested in

((Image Included))

Bas_tet [7]

Answer:

=204.13 inches.

Step-by-step explanation:

Using the side x, we can use sine to find the hypotenuse of the triangle with the angle marked 30°.

Sin 30 =x/hypotenuse.

sin 30 = 27/hyp

hyp= 27/sin 30

=54 inches

We can also find the adjacent as follows.

Cos 30 = adjacent/ 54

Adjacent= 54 cos 30

=46.77 inches

Using the angles marked 45 we can find the hypotenuse of the isosceles triangle.

sin 45= x/hypotenuse

sin 45 =27/hypotenuse

hypotenuse = 27/sin 45

=38.18 inches

The hypotenuse of both the triangles making the isosceles triangle are 38.18 inches long.

Perimeter = 54+ 46.77+27+ 38.18+38.18

=204.13 inches.

6 0

2 years ago

Read 2 more answers

The condition_______?proves that ∆ABC and ∆EFG are congruent by the SAS criterion.

snow_lady [41]

Answer:

(1) D.Angle C is congruent to to Angle F. (2) C. SSS. (3) C. cannot be congruent to.

Step-by-step explanation:

From the given figure it is noticed that

$AC=EG$

$CB=GF$

According to SAS postulate, if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then both triangles are congruent.

The included angles of congruent sides are angle C and angle G.

So, condition "Angle C is congruent to to Angle F" will prove that the ∆ABC and ∆EFG are congruent by the SAS criterion.

If $AB\neq EF$

According to SSS postulate, if all three sides in one triangle are congruent to the corresponding sides in the other.

Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore SSS criterion for congruence is violated.

Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore the included angle of congruent sides are different.

$\angle C\neq \angle G$

Therefore angle C and angle F cannot be congruent to each other.

4 0

3 years ago

Kurt deposited money into his bank account every month. The amount of money he deposited in the first 5 months of 2014 is listed

Irina-Kira [14]

Answer:

that is the answer

Step-by-step explanation:

3 1

2 years ago

Read 2 more answers

Can you help me solve this radical equation √y-10 = y-2 the sqrt sign is only over the y-10

matrenka [14]

$D:y-10\geq0 \wedge y-2\geq0\\
D:y\geq10 \wedge y\geq2\\
D:y\geq10\\\\
\sqrt{y-10}=y-2\\
y-10=(y-2)^2\\
y-10=y^2-4y+4\\
y^2-5y+14=0\\
\Delta=(-5)^2-4\cdot1\cdot14=25-56=-31\\
\Delta$