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ivanzaharov [21]
2 years ago
13

Solve each equation by completing the square NEED THIS IN 10 MINS WILL GIVE BRAINLIEST

Mathematics
1 answer:
yulyashka [42]2 years ago
4 0

Answer:

Step-by-step explanation:

7(b² - 2b - 8) = 0

7(b² - 2b +   ) = 8

7(b² - 2b + 1) = 8 + 1

7(b - 1)² = 9

(b - 1)² = 9/7

b - 1 = ±√(9/7)

b = 1 ±3√(1/7)

b ≈ -0.134, 2.134

m² + 10m + 14  = -7

m² + 10m +      = -7 - 14

m² + 10m + 25 = -7 - 14 + 25

(m + 5)² = 4

m + 5 = 2

m = -3

p² - 8p + 21 = 6

p² - 8p +     = 6 -21

p² - 8p + 16 = 6 -21 + 16

(p - 4)² = 1

p - 4 = 1

p = 5

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The final answer will be negative because a positive divided by a negative is a negative. Let's condense this into...
-(158÷135)
How many 135s are in 158? One, because two "135s" (which is 270) is greater than 158, but 135 isn't. So we know the mixed number will be 1 + (a fraction). What's the Fraction? We can find this by subtracting 135 from 158, (158 - 135) = 23. The fraction is 23/158.

The answer is, -1, 23/158.

7 0
3 years ago
The quotient of 4 and the difference of an integer and 3 is the same as two-thirds. Find the integer.
quester [9]
To find the integer, you must cross multiply, group the same terms, then divide both side by 2:

Solution:
4/(x-3)= 2/3
12 = 2x-6
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7 0
3 years ago
Can anyone assist me with this problem ?
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Answer,

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Step-by-step explanation:

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3 0
2 years ago
If a1 = 8 and an = an-1 + 5 then find the value of a5.
Nimfa-mama [501]

Step-by-step explanation:

A1=8

A2=A1+5 plug 8 into A1 here. After getting the value, put into next equation. And repeat until you get A5

A3=A2+5

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5 0
2 years ago
8. In right triangle LMN shown below, altitude MK is drawn to LN from M. IF LM = 12 and LK =10, then
Elena-2011 [213]

The length of the KN is 4.4

Step-by-step explanation:

We know from Pythagoras theorem  

In a right angle ΔLMN  

Base² + perpendicular² = hypotenuse ²

From the properties of triangle we also know that altitudes are ⊥ on the sides they fall.

Hence ∠LKM = ∠NKM = 90 °

Given values-

LM=12

LK=10

Let KN be “s”

⇒LN= LK + KN

⇒LN= 10+x        eq 1

Coming to the Δ LKM

⇒LK²+MK²= LM²

⇒MK²= 12²-10²

⇒MK²= 44           eq 2

Now in Δ MKN

⇒MK²+ KN²= MN²

⇒44+s²= MN²       eq 3

In Δ LMN

⇒LM²+MN²= LN²

Using the values of MN² and LN² from the previous equations

⇒12² + 44+s²= (10+s) ²

⇒144+44+s²= 100+s²+20s

⇒188+s²= 100+s²+20s    cancelling the common term “s²”

⇒20s= 188-100

∴ s= 4.4

Hence the value of KN is 4.4  

8 0
3 years ago
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