A chemist has 10% and 40% solutions of acid available. How many liters of each solution should be mixed to obtain 120 liters of
1 answer:
Answer:
100 liters of 10% solution is used and 20 liters of 40% solution is used
Step-by-step explanation:
Let "X" amount of 10% solution is used. Then the amount of 40% solution used is equal to 120-X
Now
10% of X + 40% of (120-X) = 15% of 120
On solving the above equation, we get
liters
Amount of 40% solution used = 120 -X = 120-100 = 20 liters
100 liters of 10% solution is used and 20 liters of 40% solution is used
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Answer:
see the attachments for the two solutions
Step-by-step explanation:
When the given angle is opposite the shorter of the given sides, there will generally be two solutions. The exception is the case where the triangle is a right triangle (the ratio of the given sides is equal to the sine of the given angle). If the given angle is opposite the longer of the given sides, there is only one solution.
When a side and its opposite angle are given, as here, the law of sines can be used to solve the triangle(s). When the given angle is included between two given sides, the law of cosines can be used to solve the (one) triangle.
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Here, the law of sines can be used to solve the triangle:
A = arcsin(a/c·sin(C)) = arcsin(25/24·sin(70°)) = 78.19° or 101.81°
B = 180° -70° -A = 31.81° or 8.19°
b = 24·sin(B)/sin(70°) = 13.46 or 3.64
