Slope- Represented by ____ in y = mx + b (what's the blank?)

Convert the function into intercept form. Show your work. y=-x^2+5x-36

Montano1993 [528]

${ - x}^{2} + 5x + 36 \\ { - x}^{2} + 9x - 4x + 36 \\ - x \times (x - 9) - 4(x - 4) \\ \\ answer \: \: - ( x - 9) \times (x \times 4)$

3 0

3 years ago

Which equation is not equivalent to the formula r = st?

maksim [4K]

We are given the formula r = st. We evaluate each option to know the correct answer.

A.) S = r/t
r = st

B.) t = r/s
r = st

C.) s = t/r
r = t/s

<span>D.) r = ts
</span>r = st

Therefore, the correct answer among the choice given is option C. It is not equivalent to the formula.

5 0

3 years ago

Read 2 more answers

2. Peter drew two rays, AC and AP with A as a common endpoint. Which of the following statements

Ksivusya [100]

Complete question is;

Peter drew two rays, AC and AP with A as a common endpoint. Which of the following statements

might describe Peter's drawing?

I. AC and AP are parallel.

II. PAC is an angle

III. AC and AP are perpendicular

A. I and II

B. II and III

C. I and 111

D. I, II, and III

Answer:

Option B: II & III

Step-by-step explanation:

We are told that Peter drew two rays which are AC and AP.

We are told that A is a common endpoint.

If A is a common endpoint, it means the 2 rays interaction point at A is at an angle.

The angle could also be 90° which means it's possible that the rays AC and AP are perpendicular.

Thus, the correct statements that describe his drawing are: II & III

4 0

2 years ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.