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dusya [7]
4 years ago
13

What must you do to the first inequality to get to the second inequality? A. N 4 <5;n<20 b. − n 4 <5;n>−20 A. A. Add

4 to each side. B. Add –4 to each side. B. A. Divide each side by 4. B. Divide each side by –4. C. A. Subtract 4 from each side. B. Subtract –4 from each side and reverse the inequality sign. D. A. Multiply each side by 4. B. Multiply each side by –4 and reverse the inequality sign.
Mathematics
1 answer:
adell [148]4 years ago
5 0

A. You have two inequalities:

  • \dfrac{n}{4}
  • n

If you multiply the first inequality by positive number 4 (multiplying inequality by positive number doesn't change the inequality sign), then you get the inequality

4\cdot \dfrac{n}{4}

B. You have two inequalities:

  • -\dfrac{n}{4}
  • n>-20.

If you multiply the first inequality by negative number -4 (multiplying inequality by negative number changes the inequality sign), then you get the inequality

-4\cdot \left(-\dfrac{n}{4}\right)>-4\cdot 5,\\ \\n>-20.

Answer: option D.

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What percent of 92 is 23
alexira [117]
We can let the percentage be p%
list an equation out from the given information.
92 x p% = 23
Flip 92 into the other side, turning it into ÷92
P% = 23 / 92
= 0.25
0.25 can be transformed into percentage, by moving the decimal place 2 places to right. Therfore, 0.25 is equal to 25.0%, which is 25%
Therfore, 25% of 92 is 23
8 0
3 years ago
A construction crew must build 4 miles of road in one week. On Monday, they build 12 mile of road. On Tuesday, they build 13 mil
Julli [10]

\frac{19}{6} many more miles of road are left to build .

<u>Step-by-step explanation:</u>

Here we have , A construction crew must build 4 miles of road in one week. On Monday, they build 1/2 mile of road. On Tuesday, they build 1/3 mile of road.  We need to find that  How many more miles of road are left to build . Let's find out:

  • On Monday, they build 1/2 mile of road.
  • On Tuesday, they build 1/3 mile of road.  

Let Miles of road left to build is x So,

⇒ \frac{1}{2} +\frac{1}{3} +x = 4

⇒ x = 4 - (\frac{1}{2} +\frac{1}{3})

⇒ x = 4 - (\frac{1(3)+1(2)}{6} )

⇒ x = 4 - (\frac{5}{6} )

⇒ x =  (\frac{4(6)-5}{6} )

⇒ x =  \frac{24-5}{6}

⇒ x =  \frac{19}{6}

Therefore, \frac{19}{6} many more miles of road are left to build .

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