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Naya [18.7K]
3 years ago
12

3a^2 (ab^2+b^2)= How much

Mathematics
1 answer:
kiruha [24]3 years ago
8 0

Answer is 3a²b (a + b)

Step-by-step explanation:

  • Step 1: Find 3a² (ab²+b²)

⇒ 3a² (ab²+b²) = 3a³b + 3a²b² = 3a²b (a + b)

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The x and y intercept of 3x + 4y = -12
muminat
× equals negative 4 i think and y equals -3
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3 years ago
there are 4800 plastic spoons in a case there 6 box3s of spoons in each case how many spoons are in each box
Slav-nsk [51]

Sorry if im wrong but i am pretty sure that is 266

3 0
3 years ago
3+-√(-3)^2 - 4(5)(-1)
Alona [7]

Answer:

Step-by-step explanation:

Easy way to do this is step by step.  Your quadratic, from your entry, must be

5x^2-3x-1.

Step by step looks like this, one thing at a time:

x=\frac{3+\sqrt{(-3)^2-4(5)(-1)} }{2(5)} becomes

x=\frac{3+\sqrt{9-(-20)} }{10} becomes

x=\frac{3+\sqrt{9+20} }{10}

and this of course is

x=\frac{3+\sqrt{29} }{10}

Do the same with the subtraction sign to get the other solution.

If you're unsure of how to enter it into your calculator, do it step by step so you don't mess up the sign.  If you enter it incorrectly, you could end up with an imaginary number when it should be real, or a real one that should be imaginary.

Just my advice as a high school math teacher.

3 0
3 years ago
Bacteria colonies increase by 37% every 2 days. If you start with 55 microorganisms, how large would the colony be after 10 days
ahrayia [7]

The number of microorganisms that I will have after 10 days would be: 245.41 microoganisms.

<h3>How to calculate the number of microorganisms that I will have after 10 days?</h3>

To calculate the number of microorganisms that I will have after 10 days, I must perform the following operations:

We need to find 37% of 55 as shown below:

  • 55 ÷ 100 = 0.55
  • 0.55 x 37% = 20.35
  • 55 + 20.35 = 75.35

So after 2 days I will have 75.35 microorganisms.

  • 75.35 ÷ 100 = 0.75
  • 0.7535 x 37% = 27.87
  • 75.35 + 27.87 = 103.22

On the fourth day I will have: 103.22 microorganisms.

  • 103.22 ÷ 100 = 1.0322
  • 1.0322 x 37% = 38.19
  • 103.22 + 38.19 = 141.41

On the sixth day I will have 141.41 microorganisms.

  • 141.41 ÷ 100 = 1.4141
  • 1.4141 x 37% = 52.32
  • 141.41 + 52.32 = 193,73

On the eighth day I will have 193.73 microorganisms.

  • 193.73 ÷ 100 = 1.9373
  • 1.9373 x 37% = 71.68
  • 193.73 + 71.68 = 265.41

On the tenth day I will have 245.41 microoganisms.

Learn more about percentages in: brainly.com/question/13450942

#SPJ1

3 0
2 years ago
Find the circumference of both circles. Use 3.14 for pi
jenyasd209 [6]

Answer:the answer is 75.36,50.24

5 0
3 years ago
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