If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)
Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm
The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.
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In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
Answer:
if there are any less than 4.84 then yes it is.
Step-by-step explanation:
please give brainliest and hope this helps
She has 445 left after the bear ate some so
21 × 12 = 252
252 + 445 = 697 acorns
she should maybe bother the bear so he can't hibernate, or steal his food so he knows what it's like
Answer:
Maggie is 5 years old
Step-by-step explanation:
3M-4+M=16
add 4 to both sides
4M=20
Divide both sides by 4
20/4 = 5
M/Maggie is 5
Minust 5x both sides
7x-5x<5x-5x-8
2x<-8
divide by 2 both sides
x<-4
