Answer:
3b(3a+7c) i used mathpapa.com
SIN(θ) = OPPOSITE / HYPOTENUSE = X / Y
COS(θ) = ADJACENT / HYPOTENUSE = 2 / Y
TAN(θ) = OPPOSITE / ADJACENT = X / 2
CSC(θ) = 1 / SIN(θ) = 1 / (X / Y) = Y / X
SEC(θ) = 1 / COS (θ) = 1 / (2 / Y) = Y / 2
COT (θ) = 1 / TAN(θ) = 1 / (X / 2) = 2 / X
HUNEY, YOU HAVE ALL OF THE VALUES, NOW JUST SOLVE FOR X AND Y THEN...
FOR EXAMPLE:
SIN(θ) = X / Y X = Y * SIN(θ)
COS(θ) = 2 / Y Y = 2 / COS(θ)
TAN(θ) = X / 2 X = 2 * TAN(θ)
SO ON, SO FORTH HUN U GET IT
Answer:
C
Step-by-step explanation:
The formula for finding the distance between 2 points (x1, y1) and (x2, y2) is
d = √[(x2 - x1)² + (y2 - y1)²]
Here (x2, y2) = (2, 3) and (x1, y1) = (4, -3)
Plugging them gives us
d = √[(2 - 4)² + (3 - (-3))²]
d = √[(2 - 4)² + (3 + 3)²]
Answer:
2 hours and 20 minutes
Step-by-step explanation:
Answer:
A:2
B:-5
C:8
D:-147
Step-by-step explanation:
A: For this one, you can cancel out the negatives. Then just divide 14 by 7. Your final answer is 2. Final Answer : 2
B: This one you can forget about the negative for the first bit. Just divide 15 by 3 to get 5. Now the negative is only on one side of the equation so therefore we add the negative back into our answer. Final Answer : -5
C: Just divide 32 by 4 to get 8. No removal or substitution is needed for this one because both numbers are positive. Final Answer : 8
D: Multiply both numbers normally forgetting about the negative at first. 49 * 3 is 147. Now one of our numbers contain a negative so we plug back the negative into our answer. Final Answer : -147
