Answer:

Step-by-step explanation:
Given Data,
Q=23000 J
c=4.184 J/g °c
Δt= 68 °c
m=?
By using this equation,
Q=mcΔt

The answer is the first one; it is an arithmetic sequence with a common difference of -40.
Answer:
The number of students who took English and History, but not Math is 143.
Step-by-step explanation:
Denote the subject choices as follows:
<em>M</em> = a students was taking Math
<em>E</em> = a students was taking English
<em>H</em> = a students was taking History
The data provided is as follows:
N (M) = 257
N (E) = 282
N (H) = 323
n (M ∩ E) = 154
n (M ∩ H) = 171
n (E ∩ H) = 143
n (M ∩ E ∩ H) = 80
Consider the Venn diagram below.
From the provided data and the Venn diagram the value of the set E and H minus M is 143.
Thus, the number of students who took English and History, but not Math is 143.
Answer:
Option b, c and e are wonderful approaches to solve the problem.
Step-by-step explanation:
Option (b) is appropriate this is because the option is talking about Simple random sampling where random universities are chosen to remove bias.
Option (c) is correct because this is an example of Stratified sampling where two homogenous groups (private and public universities are considered) and samples are chosen at random to remove bias
Option (e) is correct because this again is an example of Simple random sampling where 60 random STEM majors are chosen at random.
Answer:
378 people
Step-by-step explanation:
60% of 630 = 0.6 × 630 = 378