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Pachacha [2.7K]

3 years ago

11

Carlos is making cookies six batches of cookies each require 1/4 cup of sugar and 3/4 cup of butter how much sugar will be neede

d to make the cookies

1 answer:

ser-zykov [4K]3 years ago

3 0

Answer:

for six batches carlos will need 1 1/2 cups of sugar and 4 1/2 cups of butter

Step-by-step explanation:

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Rachel spends 35 minutes every day exercising. How many minutes will she spend exercising over 31 days?

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1085 minutes in 31 days☺

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3 years ago

Read 2 more answers

A 95% confidence interval for a population mean is computed from a sample of size 400. Another 95% confidence interval will be c

Anna [14]

Answer:

The interval from the sample of size 400 will be approximately <u>One -half as wide</u> as the interval from the sample of size 100

Step-by-step explanation:

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the 95% confidence interval is dependent on the value of the margin of error at a constant sample mean or sample proportion

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

Here assume that $Z_{\frac{\alpha }{2} } \ and \ \sigma \$ is constant so

$E = \frac{k}{\sqrt{n} }$

=> $E \sqrt{n} = K$

=> $E_1 \sqrt{n}_1 = E_2 \sqrt{n}_2$

So let $n_1 = 400$ and $n_2 = 100$

=> $E_1 \sqrt{400} = E_2 \sqrt{100}$

=> $E_1 = \frac{\sqrt{100} }{\sqrt{400} } E_2$

=> $E_1 = \frac{1}{2 } E_2$

So From this we see that the confidence interval for a sample size of 400 will be half that with a sample size of 100

7 0

2 years ago

Can someone please help me I really need help please help me please help me thank you

alekssr [168]

Answer: None. The question asks about $4 per hour.

Step-by-step explanation: The cost changes by $4 every 2 hours.

That is $2 per hour.

6 0

3 years ago

54% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability

Degger [83]

Part B is not clear and the clear one is;

P(X ≥ 6)

Answer:

A) 0.238

B) 0.478

C) 0.114

Step-by-step explanation:

To solve this, we will make use of binomial probability formula;

P(X = x) = nCx × p^(x)•(1 - p) ^(n - x)

A) 54% of U.S. adults have very little confidence in newspapers. Thus;

p = 0.54

10 random adults are selected. Thus;

P(X = 5) = 10C5 × 0.54^(5) × (1 - 0.54)^(10 - 5)

P(X = 5) = 0.238

B) P(X ≥ 6) = P(6) + P(7) + P(8) + P(9) + P(10)

From online binomial probability calculator, we have;

P(X ≥ 6) = 0.2331 + 0.1564 + 0.0688 + 0.01796 + 0.0021 = 0.47836 ≈ 0.478

C) P(x<4) = P(3) + P(2) + P(1) + P(0)

Again with online binomial probability calculations, we have;

P(x<4) = 0.1141 ≈ 0.114

5 0

3 years ago

4. If you invested $10,000 at 3.8% compounded hourly for five years, what would be your

Virty [35]

Step-by-step explanation:

The final balance is $12,088.87.

The total compound interest is $2,088.87.

4 0

3 years ago