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Paladinen [302]
2 years ago
6

What are the zeros of this function?

Mathematics
1 answer:
MrMuchimi2 years ago
8 0
Es esta la correcta

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I need help ;^; please​
Andru [333]

Answer:

\sqrt{3 {x}^{2} {y}^{3}  }  \times 2 \sqrt{72 {x}^{3} {y}^{4}  }  \\  = 2 \sqrt{3 {x}^{2} {y}^{3}  72 {x}^{3}  {y}^{4} }  \\  = 2 \times 6 \sqrt{6}  \times  \sqrt{ {x}^{5}  {y}^{7} }  \\ 12 \sqrt{6}  {x}^{2}  {y}^{3}  \sqrt{xy }  \\ 12 {x}^{2}  {y}^{3}  \sqrt{6xy}  \\ thank \: you

8 0
3 years ago
5x +4y=8 how do you transform that equation into Y=mx+b​
Karolina [17]

1. subtract 5x on both sides

2. divide by 4 on both sides

Answer:

y= -5/4x + 2

7 0
3 years ago
Jim needs 4 ½ cups of bleach for every ten gallons of water for cleaning. How many cups of bleach should he use if he is making
Ilya [14]

Answer:

2 1/4 cups of bleach

Step-by-step explanation:

4.5/10=0.45

0.45×5=2.25

6 0
2 years ago
Find the area and circumference of each circle.
ale4655 [162]

Area = πr^2

Circumference = 2πr

Blue:

Area = 5^2 = 25π

Circumference = 2 * 5 * π = 10π

Pink:

Area = 6^2 = 36π

Circumference = 2 *6*π = 12π

White:

r = 3

Area = 3^2 = 9π

Circumference = 2 *3 = 6π

Red:

Area = 7^2 = 49π

Circumference = 2 *7 = 14π

4 0
3 years ago
Derivative of g(x) = (2ra^(rx)+n)^p ?
ycow [4]
The main formula of derivative
if g(x) = a^x, so g'(x) =  a^x. lna, a>0, a # 1, 
so g ' (x) = [(2ra^(rx)+n)^p] = 2r.a^(rx)+n)^p . ln a
so g ' (x) = 2r. ln a. a^(rx)+n)^p 
3 0
3 years ago
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