What are the zeros of this function?

Mathematics

1 answer:

MrMuchimi3 years ago

8 0

Es esta la correcta

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G(r)=−5r+13 g(3)= I'm still confused on how to do this

SashulF [63]

If you're solving for g then move all terms to the left side and set equal to zero. Then set each factor equal to zero.

And your answer becomes $g=\frac{5r}{r-39}$

If you're solving for r then then move all terms to the left side and set equal to zero. Then set each factor equal to zero and your answer is $r=\frac{39g}{g-5}$

6 0

4 years ago

To avoid a storm, a passenger-jet pilot descended 0.39 mile in 0.6 minute. What was the plane's average change of altitude per m

BigorU [14]

Answer:

-0.55 per min

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Help me please anyone I need help asap

Lera25 [3.4K]

156cm=1.56m=0.0156km

5 0

3 years ago

Need help with this please.

sp2606 [1]

Answer:

$y = -\frac{3}{2} x + 4$

Step-by-step explanation:

First, let us find the gradient of AB:

Gradient of AB = $\frac{-1-3}{-1-5}$

= $\frac{2}{3}$

We also need to know that The product of gradients which are perpendicular to each other is -1. Using this idea, we can find the gradient of the perpendicular bisector:

(Gradient of perpendicular bisector)( $\frac{2}{3}$ ) = -1

Gradient of perpendicular bisector = $-\frac{3}{2}$

Now, we need to know at which coordinates the perpendicular bisector intersects AB. A perpendicular bisector bisects a line to two equal parts. Hence the coordinates of the intersection point is the midpoint of AB. Thus,

Coordinates of intersection = ( $\frac{-1 + 5}{2}$ , $\frac{-1 + 3}{2}$ )

= ( 2, 1 )

Now, we can construct our equation. The equation of a line can be formed using the formula $(y - y_{1}) = m(x - x_{1})$ where $m$ is the gradient and the line passes through $(x_{1} , y_{1} )$ . Hence by substituting the values, we get: