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MatroZZZ [7]
3 years ago
15

I need a Python program that will read a data file, perform an analysis, and write the results to a separate file with a .txt ex

tension. The data is the September temperature anomalies from 1910 to 2020 in North America. I want the program to find the average temperature anomaly of each decade, find the decade with the lowest average anomaly, and the decade with the highest average anomaly. After that the program needs to write its results on a separate .txt file.
Here is the data:

1910,-0.21
1911,-0.08
1912,-0.86
1913,-0.94
1914,-0.19
1915,-0.51
1916,-0.37
1917,-0.07
1918,-0.90
1919,0.21
1920,0.00
1921,0.12
1922,0.32
1923,0.08
1924,-0.63
1925,0.27
1926,-0.65
1927,-0.01
1928,-0.59
1929,-0.42
1930,0.15
1931,1.07
1932,0.17
1933,0.52
1934,-0.78
1935,-0.20
1936,0.12
1937,0.47
1938,1.35
1939,0.30
1940,1.01
1941,-0.39
1942,-0.23
1943,-0.04
1944,0.39
1945,-0.34
1946,0.10
1947,0.11
1948,0.66
1949,0.01
1950,-0.05
1951,-0.07
1952,0.32
1953,0.38
1954,0.39
1955,0.02
1956,-0.48
1957,0.30
1958,0.23
1959,-0.03
1960,0.44
1961,-0.57
1962,-0.19
1963,0.45
1964,-0.62
1965,-1.44
1966,0.47
1967,0.38
1968,0.04
1969,-0.04
1970,-0.44
1971,-0.07
1972,-1.12
1973,0.12
1974,-1.08
1975,-0.50
1976,0.24
1977,0.46
1978,0.22
1979,0.41
1980,-0.16
1981,0.22
1982,-0.10
1983,0.06
1984,-0.94
1985,-0.61
1986,-0.43
1987,0.76
1988,0.01
1989,0.16
1990,0.79
1991,0.10
1992,-1.01
1993,-0.57
1994,0.58
1995,0.56
1996,-0.16
1997,1.24
1998,1.70
1999,0.37
2000,0.20
2001,1.11
2002,1.00
2003,0.60
2004,0.24
2005,1.15
2006,0.56
2007,0.57
2008,0.35
2009,1.49
2010,0.82
2011,1.41
2012,1.40
2013,1.39
2014,0.75
2015,1.51
2016,1.39
2017,1.41
2018,0.31
2019,1.72
2020,0.73
Computers and Technology
2 answers:
Over [174]3 years ago
8 0

Answer:

You can follow below approach to open file and read from it. myfile = open("/Users/David/Desktop/test. txt","r") #returns file handle myfile. read() # reading from the file myfile.

Explanation:

melamori03 [73]3 years ago
6 0

Answer:

Given the size and tremendous heat capacity of the global oceans, it takes a massive amount of heat energy to raise Earth’s average yearly surface temperature even a small amount. The 2-degree increase in global average surface temperature that has occurred since the pre-industrial era (1880-1900) might seem small, but it means a significant increase in accumulated heat. That extra heat is driving regional and seasonal temperature extremes, reducing snow cover and sea ice, intensifying heavy rainfall, and changing habitat ranges for plants and animals—expanding some and shrinking others.  

Explanation:

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Answer:

the first argument listed after IF

Explanation:

The Logical... argument in an IF function formula is always the first argument listed after IF.  And the second option is the value to be printed if the logical...argument is true, and if it is false then the value mentioned as third argument is assigned, or printed. And the logical...argument never comes before the IF function formula. Hence, the right option is the first argument.

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Answer:

while(inFile >> intOne >> intTwo)

Explanation:

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The scheme function (mult2-diff Ist) should take one argument, a list of numbers, and results in multiplying each number in the
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Answer:

The solution code is written in Python.

  1. def mult2_diff(lst):
  2.    num_list = []
  3.    for x in lst:
  4.        num_list.append(x * 2)
  5.    diff = num_list[0]
  6.    for i in range(1, len(num_list)):
  7.        diff = diff - num_list[i]
  8.    
  9.    print(diff)

Explanation:

Firstly, based on the requirement stated in the question, define a function <em>mult2_diff() </em>that takes one argument, <em>lst</em>, which is a list of numbers (Line 1).

This function is expected to multiply each number in the list by two and then followed with computing the difference. To do so, let's try to attempt the first function task, multiplying numbers.  Create a new list, num_list, to hold the multiplied numbers (Line 2). Use a for loop to traverse through each number in the input list, <em>lst</em>, and multiply each of them by two and add it to the <em>num_list </em>(Line 4-5).

To attempt the second function task, create another variable, <em>diff</em>, to hold the value of calculated difference between the numbers in the <em>num_list</em>. Initialize <em>diff </em>with the first number in the <em>num_list</em>. Use a another for-loop to traverse through each number in the num_list starting with second index, <em>1</em>, and calculate the difference between the <em>diff </em>and the current number extracted from the <em>num_list </em>through indexing.

At last print the output of <em>diff</em> (Line 11).

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