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klemol [59]
2 years ago
5

Find the perimeter please will mark brainliest

Mathematics
1 answer:
N76 [4]2 years ago
7 0
The perimeter is 12.5
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EASY points here Solve for H; P=2L+2H
e-lub [12.9K]
P=2L+2H
First, isolate 2H:
2H=P-2L
Second, get a singular value of H (just H):
2H/2=(P-2L)/2

Final answer: 

H=\frac{P-2L}{2}
7 0
2 years ago
Read 2 more answers
What are the areas of each smaller rectangle and the large rectangle?
zhannawk [14.2K]

Answer:

Area of part 1: 3 * 5\sqrt{2} = 15\sqrt{2}

Area of part 2: 3\sqrt{2} * 5\sqrt{2}=30

Area of entire rectangle: 30 + 15\sqrt{2}

Step-by-step explanation:

The area of a rectangle can be found by using formula : length * width.

The area of part 1 can be simplified to this:

3 * 5\sqrt{2} = 15\sqrt{2}

Area of part 2:

3\sqrt{2} * 5\sqrt{2}=30

The area of the entire rectangle can simply be added from part 1 and part 2.

For area 2, remember multiplying the square root of 2 twice nullifies the square root. So it becomes 15 * 2, which is equal to 30.

7 0
3 years ago
What is the area of a rectangle if 1 base is 14 in, the 2nd base is 3.5 in and the height is 8 in?​
algol13

Check the picture below.

notice, we have three pair of sides, let's add them all up to get the area

\stackrel{\textit{left and right}}{2(8\cdot 14)}+\stackrel{\textit{front and back}}{2(3.5\cdot 8)}+\stackrel{\textit{top and bottom}}{2(3.5\cdot 14)}\implies 378~in^2

5 0
2 years ago
I have 2 similar right angle triangles, CDE and ADG. The length of CDE's hypotenuse is 1/3 the length of ADG's hypotenuse. The a
Orlov [11]
<span>lengths are in ratio 1:3
areas are in ratio
1 : 3</span>²<span> = 1: 9
area of ADG = 9 x 42 = 378 </span>
8 0
3 years ago
Which of these professionals most directly uses geometry?
Pavel [41]
MEDICAL IMAGING SPECIALIST
7 0
3 years ago
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