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marusya05 [52]
3 years ago
6

Can someone solve this please ill give Brainly to who ever is first :)!

Mathematics
1 answer:
natima [27]3 years ago
6 0

Answer:

465 in²

Step-by-step explanation:

square area: A = lw

triangle area: A = \frac{1}{2} lw (or base x height)

A_{square} = (15)(15) = 225

A_{triangle} = \frac{1}{2} (8)(15) = 60

There is one square and 4 triangles so...

225 + 4(60) = 465 in²

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Henry leads a team of hikers for a full-day hike that takes 8 hours. Every hour, the hikers gain 250 feet in elevation. • The in
Arisa [49]

The missing blanks have been filled.

<h3>What is a Function ?</h3>

A function is a mathematical statement used to relate a dependent and an independent variable.

It is given that

Total time taken to hike is 8 hours

Let the time taken in hours is represented by t

and the elevation is represented by h

Every hour, the hikers gain 250 feet in elevation.

The independent variable is<u> t ,</u><u> time taken</u> to hike , in<u> </u><u>hours</u> .

The dependent variable is h , increased elevation in feet or<u> elevation the hikers have gained .</u>

<u />

A possible verbal description is <u>Elevation </u><u>at any given time</u> equals 250 <u>times the time taken to hike.</u>

The equation<u> </u><u>h </u>=<u> 250 t </u>corresponds to the relationship.

To know more about Function

brainly.com/question/12431044

#SPJ1

4 0
2 years ago
Pls help asap will gibe brainlist
MrMuchimi

Answer:

✧ First , I splited the given figure into three parts namely ABCD , EFGH & lastly IJKL ( See the attached picture). Now , We're gonna find out the area of these rectangles :

  • Area of ▭ ABCD = Length × Breadth = 12 × 8 = 96 in²
  • Area of ▭ EFGH = Length × Breadth = 13 × 4 = 52 in²
  • Area of ▭ IJKL = Length × Breadth = 12 × 6 = 72 in²

♨ Now , Adding the area of ▭ ABCD , ▭ EFGH & ▭ IJKL :

☂ Total Area of the figure : 96 in² + 52 in² + 72 in² = \boxed{ \large{ \underline{ \tt{220 \:  {in}^{2} }}}}

☄ Hope I helped! ♡

♪ Have a wonderful day / night ! ♕

✎ \underbrace{ \overbrace{ \mathfrak{Carry \: On \:Learning}}} ☃

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

8 0
3 years ago
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