Answer:
4x^2+19x-5=(x+5)(4x -1)
Step-by-step explanation:
The given expression is 4x^2 + 19x - 5
The leading coefficient is 4 and last term is -5
Multiply them, we get -20
Now find the factors of -20 such that when you add the factors we have to get 19.
-1*20 = -20
20+ (-1) = 19
The right factors are -5 and 9.
4x^2 + 19x - 5 =4x^2 + 20x -1x - 5
= 4x(x + 5) -1(x + 5)
= (x + 5)(4x -1)
The missing factor is (4x -1)
Thank you.
B
because a constant term is a number with out a variable
Correct option is C). {(0, −5), (2, 9), (−3, −26)}
Given function is f(x)=7x-5.
Here, Options are given ordered pair
Let, x=0
f(x)=7x-5
f(0)=7(0)-5
f(0)=(-5)
The ordered pair is (0,-5)
Let, x=2
f(2)=7(2)-5
f(2)=9
The ordered pair is (2,9)
Let, x=(-3)
f(-3)=7(-3)-5
f(-3)=(-26)
The ordered pair is (-3,-26)
Thus, Correct option is C). {(0, −5), (2, 9), (−3, −26)}
