Answer:
domain = ( -infinity, infinity) = all real numbers
range = ( -1, infinity)
Answer:
<em>Answer is </em><em>10</em><em>/</em><em>7</em>
Step-by-step explanation:
[tex] (\frac{6}{10} )r = \frac{6}{7} \\ cancelling \: 6 \: on \: both \: sides \\ (\frac{1}{10} )r = \frac{1}{7} \\ \frac{r}{10} = \frac{1}{7} \\ r = \frac{10}{7} \: \\
<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>.</em>
Answer: The answer is ¨B¨
Step-by-step explanation:
Answer might be 9 due to my algebra teacher
Answer:
f(x) = 26500 * (0.925)^x
It will take 7 years
Step-by-step explanation:
A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. Then use your formula to determine when the value of the car will be $15,000 to the nearest year.
To find the formula we will use this formula: f(x) = a * b^x. A is our initial value which in this case is $26500. B is how much the value is increasing or decreasing. In this case it is decreasing by 7.5% per year. Since the car value is decreasing we will subtract 0.075 from 1. This will result in the formula being f(x) = 26500 * (0.925)^x. Now to find the value of the car to the nearest year of when the car will be 15000 we plug 15000 into f(x). 15000 = 26500 * (0.925)^x. First we divide both side by 26500 which will make the equation: 0.56603773584=(0.925)^x. Then we will root 0.56603773584 by 0.925. This will result in x being 7.29968 which is approximately 7 years.
