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3 years ago

Evaluate 3.6/ x for x =2

Mathematics

2 answers:

MakcuM [25]3 years ago

8 0

Answer:

1.8

Step-by-step explanation:

3.6/ x for x =2

3.6/2 = 1.8

weqwewe [10]3 years ago

8 0

Answer:

1.8

Step-by-step explanation:

3.6/ x when x= 2

Therefore, substitute the value of x.

Just divide through by 2

3.6/ 2 is 1.8

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Please help! It would be very much appreciated :)

Trava [24]

Answer:

Cos 45=6/x

x=6/cos 45=6√2

x=6√2

tan 45=y/6

y=tan45 ×6

y=6

sin 60=y/10

y=sin60×10

y=5√3

again

Cos 60=x/10

x=½×10

x=5

Sin 45=x/5

x=1/√2×5 or

x=5√2/2

again

y=5√2/2 or 5/√2[base angle of right angled isosceles triangle]

Sin 30=8/x

½×x=8

x=8*2

x=16

again

cos 30= y/x

√3/2×16=y

y=8√3

sin 60=7/x

x=7/[√3/2]

x=14/√3 or 14√3/3

again

cos 60=y/x

½×14√3/3=y

7√3/2=y

y=7√3/2

Note:

Sin angle =perpendicular/hypotenuse

Cos angle =base/hypotenuse

Tan angle =perpendicular /base

7 0

2 years ago

Find the slope of the line whose equation is 3x+6y=9. How do I solve this?

nirvana33 [79]

If you need to get to nine the answer is...
6+3 or 3x1+6

8 0

3 years ago

How many terms are in the expression shown below?

stich3 [128]

Answer:

3 terms. All of the numbers are considered terms.

Step-by-step explanation:

If it asked for variables, it would be 2.

4 0

3 years ago

Mr Davis buys 30 tickets for the drama club to attend a play. The tickets cost n dollars each for a total of $360

nalin [4]

Answer:

the answer is F. because n x 30 would = 360 and the n would be 12 so he paid 12 dollars per ticket and I got that answer by dividing the two numbers 30 and 360

brainliest plz

5 0

3 years ago

Write the quadratic function in standard form. f(x) = -x2 + 2x + 4 f(x) =

goldenfox [79]

Answer:

$f(x)=-1(x-2)^2+8$

Step-by-step explanation:

Given:

The quadratic function is given as:

$f(x)=-x^2+2x+4$

The standard form of a quadratic function is given as:

$f(x)=a(x-h)^2+k$ , where, 'a', 'h' and 'k' are real numbers.

Now, in order to convert the given function to standard form, we use completing by square method.

$-x^2+2x=-(x^2-2x)=-[(x-2)^2-2^2]=-[(x-2)^2-4]=-(x-2)^2+4$

Now, $f(x)=-x^2+2x+4$ can be rewritten as:

$f(x)=-(x-2)^2+4+4\\f(x)=-1(x-2)^2+8$

Therefore, the standard form of the function is:

$f(x)=-1(x-2)^2+8$

7 0

2 years ago