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weqwewe [10]
4 years ago
7

Please solve with working quick please

Mathematics
1 answer:
murzikaleks [220]4 years ago
6 0

Answer:

\displaystyle V=16500\ m^3

Step-by-step explanation:

<u>Volume Of A Pyramid </u>

The volume of a pyramid is computed as one third of the product of the area of the base (B) by the height (H):

\displaystyle V=\frac{1}{3}BH

<em>The question doesn't ask for anything in particular, so I'm computing the volume of the solid shown in the image </em>

We have a rectangular base of dimensions 15m x 60 m. The area of the base is

B=(15m)(60m)=900m^2

We now calculate the volume, knowing the height is 55 m

\displaystyle V=\frac{1}{3}(900\ m^2)(55\ m)

\boxed{\displaystyle V=16500\ m^3}

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8 0
3 years ago
Solve the equation for the indicated variable. Please help ASAP!!!!! :(<br> A=(730x)/(d^2) for x
zvonat [6]

First let's get rid of the d^2 in the denominator of the fraction on the right side of the equation. This will help to get only x and a coefficient on one side of the equation:

A = \dfrac{730x}{d^2}

d^2A = 730x


Now, simply divide by 730 to find x:

d^2A = 730x

\boxed{\dfrac{d^2A}{730} = x}

3 0
3 years ago
A triangle has sides lenghts of 6.8cm, 28.5cm and 29.3cm. is this a right angled triangle​
EleoNora [17]

Answer:

Yes it is a right angled triangle

Step-by-step explanation:

If its a right triangle it would satisfy the Pythagoras theorem.

29.3^2 = 858.49

28.5^2 = 812.25

6.8^2 =  46.24

Adding the last 2 values:

812.25 + 46.24

= 858.49

So YES.

6 0
2 years ago
Answer it please , thanks
a_sh-v [17]
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4 0
3 years ago
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Hello I’m trying to solve this problem I just don’t know how to do it.
Katyanochek1 [597]

Step-by-step explanation:

To evaluate the proposed, the comprehension of linear data is required,

Slope: The rise/run or the accumulative unit distance between two differentiated points on a linear.

X-intercept: The peculiar point in which the observed linear data intersects the x-axis.

Y-intercept: The peculiar point in which the observed linear data intersects the y-axis.

1. To solve the following systems, first convert the Slope-Intercept formatting to Standard (General) form:

y = -5/3x + 3

3(Y = -5/3x + 3) Product by the denominator to eliminate the fraction.

3y = -5x + 9. Add 5x to the other expression as in standard form, the slope must be positive.

5x + 3y = 9 <== Standard (General) Form.

Y = 1/3x - 3

3(y = 1/3x - 3). Product by the denominator to eliminate the fraction.

3y = x - 9. Subtract by x to place the slope within the other expression of the equation.

-1(-x + 3y = -9). Now, product by -1 to contribute to a positive slope.

X - 3y = 9 <=== Standard (General) Form.

2. To solve for the x and y values, utilize the system of substitution:

1(5x + 3y = 9)Multiply equations by opposite slope to the other, and a positive to other.

-5(X - 3y = 9)

Evaluate,

+ 5x + 3y = 9. Now, add the systems.

-5x + 15y = -45

——————————

18y = -36

Y = -2

Thus, now that y is equated to -2, substitute that to either equation.

X - 3y = 9

X - 3(-2) = 9

X + 6 = 9

X = 3

Thus, x = 3, y = -2. This is their intersection point.

To plot these lines on the graph, execute the following,

Y = -5/3 x + 3

Start with the y-intercept. Draw a point on number 3 on the y-axis (vertical).

Starting with that point, go down 5 units, right 3 units.

* Remember, if there is a negative rise, go down. Positive, go up. If there is a negative run, go left. Positive, go right.

* Keep going 5 units down, right 3 units, until the graph allows.

2. Y = 1/3 x - 3

Similarly, conduct the same steps:

Starting with the y-intercept, draw a point on -3 on the vertical, or y-axis.

Beginning on that point, go up 1 unit, right 3 units.

Keep going up 1 units and 3 units right until the graph permits.

*I hope this helps.

3 0
3 years ago
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