Help! I don’t know how to find it..

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

6 0

What is it all i see is black

boyakko [2]3 years ago

4 0

It is just a black picture

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There are 16 pieces of fruit in a basket, including 2 nectarines. What is the probability that a randomly selected piece of frui

aleksklad [387]

Answer:

The probability is 1/8

Step-by-step explanation:

We have 2 nectarines in a total of 16 pieces of fruit in a basket, so the probability of random selected piece of fruit being a nectarine is the number of nectarines over the total number of pieces of fruit:

Probability = Number of nectarines / Total pieces = 2 / 16

To find the fraction in the simplest form, we divide the numerator and denominator by 2:

Probability = (2/2) / (16/2) = 1/8

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4 years ago

7x to the 2nd power when x=6

topjm [15]

Your answer would be 252 Hope this helps

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3 years ago

What is the value of X? Intersecting Chords (Lengths)

quester [9]

Answer:

x = 4

Step-by-step explanation:

(8)(7) = 14x

14x = 56

x = 4

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3 years ago

For a certain candy, 20% of the pieces are yellow, 15% are red, 20% are blue, 20% are green, and the rest are brown. a

OLEGan [10]

Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

Brown: $\frac{25}{100}$
Yellow or Blue: $\frac{20}{100} +\frac{20}{100} = \frac{40}{100}$ ....add the numerators

Not Green: $\frac{80}{100}$ .... since the sum of all the rest is 80%

Stiped: $\frac{25}{100}$ .... there are 0 striped candies.

Assuming the ratios/percentages of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.