1 year old is smaller and his brain its less develop den the 2 years old
Answer:

Step-by-step explanation:
If we approximate the binomial distribution with a normal distribution, we have to apply a correction factor for the fact that we are now dealing with a continuous variable instead of a discrete one, as it was with the binomial distribution.
The probability of no more than 35 defective CDs: P(X<35)
In this case, as X=35 is not included in the interval, we start the interval from X=35-0.5=34.5.

being Pb the probability under the binomial distribution and Pn the probability under the normal distribution.
The area for the normal distribution is the one below X=34 (or P(X<34)).
Answer:
<h2>k = 7</h2>
Step-by-step explanation:

Answer:

Step-by-step explanation:
Given


Required
Determine LN
Since LM is a bisector, then we have:
(See attachment for illustration)

Collect Like Terms


Solve for w


LN is calculated as thus:

Substitute 4 for w


