Have the kids answer questions, if correct they get to shoot a small ball into a garbage can for extra points! FUN!
~Hope This Helps! <3
Answer:
The correct answer is 15 cm.
Step-by-step explanation:
Let the width of the required poster be a cm.
We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.
Similarly total margin combining both the sides is (4+4=) 8 cm.
So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } 
This area is equal to 125
as per as the given problem.
∴ (a - 10) × (a - 8) = 125
⇒
- 18 a +80 -125 =0
⇒
- 18 a -45 = 0
⇒ (a-15) (a-3) = 0
By law of trichotomy the possible values of a are 15 and 3.
But a=3 is absurd as a
4.
Thus the required answer is 15 cm.
Using the formula given for area:
Area = 1/2 (7 +5)4 = 1/2(12)4 = 24 square cm.
Now to find the volume multiply the area by the depth:
24 x 6 = 144 cubic cm.
If it involves an Arc, the inscribed angle is 1/2 of the measure of the are across from it. If the figure inscribed in a quadrilateral, opposite angles are supplementary (when added together equals 180 degrees) This is all I know :)
1. -21
2. −39
3.−42
4. -5
5. −3
for the other question u can use calculator :)