Answer:
The correct answer is option A.
Step-by-step explanation:
Given : line AB intersect CD at P. PR is perpendicular to AB.
∠APD = 170°
To find = ∠DPB =?
Solution :
line AB intersect CD at P:
So,∠APD =∠BPC = 170° ..[1]
(vertically opposite angles of two straight lines intersecting at common point are equal)
On line CD two angles are ∠BPC ,∠DPB
∠BPC + ∠DPB =180° (supplementary angles)
170°+ ∠DPB =180°
∠DPB =180° - 170° = 10°
So, the measure of ∠DPB is 10°.
You basically have a triangle and a rectangle. seperate the two at first, the rectangle's area is 32 since 8*4=32
the area of a triangle is half of it's base times width. so 3*5=15/2=7.5
add 7.5 and 32 to get 39.5
Answer:
880
Step-by-step explanation:
8% equals 0.08, 0.08 x 11000 = 880
Sorry if I was wrong I tried my best.
Answer: The difference cannot be found because the indices of the radicals are not the same.
Step-by-step explanation:
To find the difference you need to subtract the radicals. But it is important ot remember the following: To make the subtraction of radicals, the indices and the radicand must be the same.
In this case you have these radicals:
![\sqrt[ {8ab}^{3} ]{{ac}^{2} }- \sqrt[ {14ab}^{3}]{{ac}^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B%20%7B8ab%7D%5E%7B3%7D%20%5D%7B%7Bac%7D%5E%7B2%7D%20%7D-%20%5Csqrt%5B%20%7B14ab%7D%5E%7B3%7D%5D%7B%7Bac%7D%5E%7B2%7D%20%7D)
You can observe that the radicands are the same, but their indices are not the same.
Therefore, since the indices are different you cannot subtract these radicals.