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2 years ago

Please its due in tommorow no lie!

Mathematics

1 answer:

Nezavi [6.7K]2 years ago

7 0

First question is 1.40 because i read the question wrong
my sister said its 75p

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Find the equation of the line that has a slope of -3 and passes through (4, 4)

sergey [27]

$The\ slope-point\ form:y-y_1=m(x-x_1)\\The\ slope-intercept\ form:y=mx+b\\--------------------\\m=-3;\ (4;\ 4)\to x_1=4\ and\ y_1=4\\\\\boxed{y-4=-3(x-4)}\\\\y-4=-3x+12\ \ \ |add\ 4\ to\ both\ sides\\\boxed{y=-3x+16}$

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2 years ago

Patricia is 5 years older than Wyatt. The sum of their ages is 61. How old are Patricia and Wyatt?

baherus [9]

Answer

w+(w+5)=61

Step-by-step explanation:

4 0

2 years ago

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You have a bag of 12 blue marbles and 12 red marbles. each are labeled 1-12. so you have 24 marbles in total (1-12 for each colo

Softa [21]

Answer:

The probability of the first marble being blue and second being red is a 50/50 because you have 12 red and 12 blue so 50/50

Step-by-step explanation:

8 0

2 years ago

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50× 3/8 how to reduce answer to lowest te

hoa [83]

The lowest term is $\frac{75}{4}$ .

Solution:

Given expression is $50\times\frac{3}{8}$

To reduce this term to the lowest term:

$$50\times\frac{3}{8}=\frac{50}{1}\times\frac{3}{8}$

Multiply the numerator and denominator.

$$50\times\frac{3}{8}=\frac{150}{8}$

Now, divide the numerator and denominator by the greatest common factor.

Here 150 and 8 both have common factor 2.

So, divide numerator and denominator by 2.

$$=\frac{150\div2}{8\div2}$

$$=\frac{75}{4}$

$$50\times\frac{3}{8}=\frac{75}{4}$

Hence the lowest term is $\frac{75}{4}$ .

4 0

2 years ago

A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

3 0

2 years ago