Recall that for
, i.e. a random variable
following a binomial distribution over
trials and with probability parameter
,
So you have
The expected value of
is simply
, while the standard deviation is
. In this case, they are
and
, respectively.
Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
Answer:
I can maybe!
OK, sorry it took me so long I wanted to make sure I gave you the best answer I could so I had to think a little. Anyway. If I had to pick one I would choose...
D. The value of g(x) is determined by the value of h times x.
I really hope this helps! I tried my best!
It would be -6 x+9 i think.
