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3 years ago

7 - (-11) = _ Please help having trouble with answer

Mathematics

1 answer:

stepladder [879]3 years ago

8 0

Use long addition to evaluate: the answer is 18

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Find the following algebra, I am in class and plz give explanation

Lelechka [254]

1) Solving $4a+4b-ac-bc$ we get $(a+b)(4-c)$

2) Solving $16a^4-8b$ we get $8(2a^4-b)$

3) Solving $x^2-8x+15$ we get $(x-3)(x-5)$

Step-by-step explanation:

We need to solve the following expressions:

1) $4a+4b-ac-bc$

We will solve this expression by factoring common terms:

$4a+4b-ac-bc$

Factoring 4 from 4a+4b and -c from -ac-bc

$4(a+b)-c(a+b)$

Taking common term

$(a+b)(4-c)$

2) $16a^4-8b$

We will solve this expression by factoring common terms:

$16a^4-8b$

Taking 8 as common term:

$8(2a^4-b)$

3) $x^2-8x+15$

We can solve the expression by breaking the middle term into 2

$x^2-3x-5x+15\\Finding\,\,common:\\=x(x-3)-5(x-3)\\=(x-3)(x-5)$

Keywords: Finding factors

Learn more about Finding factors at:

#learnwithBrainly

6 0

3 years ago

Solving Rational equations. LCD method. Show work. Image attached.

Ugo [173]

Answer:

$k=\frac{1}{2}$

Step-by-step explanation:

The given rational equation is

$\frac{5k}{k+2}+\frac{2}{k}=5$

The Least Common Denominator is

$k(k+2)$

Multiply each term by the LCD.

$k(k+2)\times \frac{5k}{k+2}+k(k+2)\times \frac{2}{k}=5k(k+2)$

Simplify;

$k\times \frac{5k}{1}+(k+2)\times \frac{2}{1}=5k(k+2)$

$\Rightarrow k(5k)+2(k+2)=5k(k+2)$

Expand;

$\Rightarrow 5k^2+2k+4=5k^2+10k$

Group similar terms;

$\Rightarrow 5k^2-5k^2+2k-10k=-4$

$\Rightarrow -8k=-4$

Divide by -8.

$k=\frac{1}{2}$

5 0

3 years ago

PLS HELP I WILL GIVE BRAINLEST

yan [13]

Answer:

he earns 69 dollars

Step-by-step explanation:

1st grade question now give brainliest 5 stars and heart

6 0

3 years ago

Read 2 more answers

Together Juan and Maria can clean the house in 6 hours. Alone Juan can complete the job 2 hours faster than Maria. Find to the n

MaRussiya [10]

Answer:

the correct answer is 50 really hope this helped :)

Step-by-step explanation:

8 0

3 years ago

The table shows the price p, for renting for a d days from a car rental company?

masha68 [24]

$\bf \begin{array}{|cc|ll} \cline{1-2} \stackrel{Days}{d}&\stackrel{Price}{P}\\ \cline{1-2} 1&\$115\\ 2&\$150&\leftarrow 115+\stackrel{35(1)}{35}\\ 3&\$185&\leftarrow 115+\stackrel{35(2)}{35+35}\\ 4&\$220&\leftarrow 115+\stackrel{35(3)}{35+35+35}\\ d&&\leftarrow 115+35d\\ \cline{1-2} \end{array}~\hfill \stackrel{part~A}{P(d)=35d+115} \\\\\\ ~\hspace{34em}$

part B)

the slope is always in a linear equation, the coefficient of the independent variable, in this case namely "35".

35 or 35/1 dollars/day means

for every passing day the car is rented out, the charge is $35, so if you rent the car "d" days, you'll be charged 35d.

7 0

3 years ago