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Radda [10]
3 years ago
8

Find the slope in each line

Mathematics
1 answer:
Maslowich3 years ago
5 0
Can you put the YX just because it’s too blurry.
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Nora spent a total of 8 1/6 hours on community service last year. Given that her visit to the old folks' home made up 4/7 of the
Anna007 [38]
That would be 8 1/6  * 4/7  =  49/6 * 4/7 =  7*4 / 6 =  28/6 = 4 4/6 = 4 2/3

Answer is 4 2/3 hours
3 0
3 years ago
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Nolan drew a right triangle. how many acute angles did he drew?
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2 acute angles because all of the angles of the triangle must add up to 180 degrees. If you used 90 degrees already you only have 90 degrees left to make the other two angles.
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3 years ago
What is the equation of the line that has a slope of 1/4 and a Y intercept of -3
Papessa [141]

Solution:

we have been asked to find

The equation of the line that has a slope of 1/4 and a Y intercept of -3.

The standard equation of straight line in the slope-intercept form is given by the formula

y=mx+b

where m is the slope of the straight line and b is the y-intercept.

Substitute the given values we get

y=\frac{1}{4}x-3\\

Hence the equation of the line that has a slope of 1/4 and a Y intercept of -3 is y=\frac{1}{4}x-3\\

4 0
3 years ago
A parallelogram has an area of 37.72 m2 and a height of 4.6 m. How long is the base of the parallelogram?
DIA [1.3K]
The base is 8.6, you just take the area divided by the height and you have your length or base
8 0
3 years ago
Read 2 more answers
Help me pls need help​
frez [133]

Problem 1

w = width

w+36 = length, because it's 36 feet longer compared to the width

=======================================================

Problem 2

The area w(w+36) is less than 2040, and it's also larger than 0.

We can write that as 0 \le w(w+360) \le 2040 which is the same as 0 \le w^2+360w \le 2040

If you wanted to drop the first part, then you can say either w(w+360) \le 2040 or w^2+360w \le 2040

I used the formula area = length*width

=======================================================

Problem 3

There are many possibilities here. Let's say w = 10 feet. If so then the length would be w+36 = 10+36 = 46 feet. This 10 by 46 rectangle has an area of 10*46 = 460 square feet which is under the 2040 sq ft limit.

Another possibility is that w = 20 ft and w+36 = 56. This 20 by 56 rectangle has an area of 20*56 = 1120 sq ft.

It turns out you can pick any value of w between 1 and 30, assuming you only restrict yourself to integers. You can find the largest possible value of w by solving the equation w(w+36) = 2040. The positive solution to this equation is roughly w = 30.62

Side note: even though something like w = 1 is possible, it's not very realistic. A conference hall that's only 1 ft wide won't be able to fit a person comfortably unless they don't mind being sandwiched between two walls and have to walk sideways.

=======================================================

Problem 4

If you solved w(w+36) = 360 with a graphing calculator or the quadratic formula, then you would find the positive solution for w is roughly 8.15

If your teacher is considering positive real numbers, then this is realistic; however, if they are only considering positive integers, then something like w = 8.15 isn't possible.

5 0
3 years ago
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