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Kryger [21]
3 years ago
5

How many atoms does 6.022x10^23 formula units if water have

Chemistry
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

one mole of water contains 6.02 x 1023 MOLECULES of water.

But each molecule of water contains 2 H and 1 O atom = 3 atoms, so there are approximately 1.8 x 1024 atoms in a mole of water.

Explanation:

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Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions.
Norma-Jean [14]

2 KHP(aq) + Ba(OH)_{2}(aq) ---> KP_{2}Ba (aq) + 2 H_{2}O (l)\

Moles of Ba(OH)_{2}=0.483 \frac{mol}{L} * 28.5 mL *\frac{1 L}{1000mL}  = 0.0138 mol Ba(OH)_{2}

Mass of KHP = 0.0138 mol Ba(OH)_{2} * \frac{2 mol KHP}{1 mol Ba(OH)_{2}}  * \frac{204.22 g KHP}{1mol KHP}

= 5.64 g KHP

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4 years ago
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6. A hot potato is sitting out on the counter. After 3 hours, you pick up the 5 points
vovikov84 [41]

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the heat differs to the air as heat is energy and energy likes to travel

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2 years ago
If ice is warmed and becomes a liquid, which type of process is it ?
attashe74 [19]

The answer is Endothermic

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3 years ago
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A student measures the mass of a 6.0 cm3 block of brown sugar to be 10.0 g. What is the density of the brown sugar?
Alex17521 [72]

Answer:

1.67g/cm3

Explanation:

The formula for density is d=\frac{m}{v} . The m variable stands for mass and the v variable stands for volume.

The mass of the brown sugar is 10.0g and the volume is 6.0cm3, so we can plug those values into the equation.

d=\frac{10g}{6cm^{3} }

d=1.67\frac{g}{cm^{3} }

Rounded to 3 significant figures, the density of the block of brown sugar is 1.67 g/cm3. If the mass is in grams and the volume is in cm3, the unit for the final answer is \frac{g}{cm^{3} } (grams per centimetres cubed).

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4 years ago
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What mass of oxygen (O2) forms in a reaction that forms 15.90 g C6H12O6? (Molar mass of O2 = 32.00 g/mol; molar mass of C6H12O6
Dafna11 [192]

The answer is: the mass of oxygen is 16.95 grams.

The overall balanced photosynthesis reaction:  

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂.  

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n(C₆H₁₂O₆) = m(C₆H₁₂O₆) ÷ M(C₆H₁₂O₆).

n(C₆H₁₂O₆) = 15.9 g ÷ 180.18 g/mol.

n(C₆H₁₂O₆) = 0.088 mol; amount of glucose.

From chemical reaction: n(C₆H₁₂O₆) : n(O₂) = 1 : 6.

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m(O₂) = 16.95 g; mass of oxygen.

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