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ValentinkaMS [17]
3 years ago
10

Suppose m = 2 + 6i, and║m + n║ = 3√10, where n is a complex number.

Mathematics
2 answers:
Illusion [34]3 years ago
8 0

Answer:

the modulus of a complex number z = a + bi is:

Izl= √(a²+b²)

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a + bi

Im + nl = 3√10

√(a² + b²+ 2²+ 6²)= 3√10

√(a^2 + b^2 + 40) = 3√10

squaring both side

a²+b²+40 = 3^2*10 = 9*10 =90

a²+b²= 90 - 40

a²+b²=50

So,

|n|=√(a^2 + b^2) = √50

The modulus of n must be equal to the square root of 50.

now

values a and b such

a^2 + b^2 = 50.

for example, a = 5 and b = 5

5²+5²=25+25= 50

Then a possible value for n is:

n = 5+5i

BabaBlast [244]3 years ago
5 0

Answer:

For a, I got √10 for the minimum value of modulus n.

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Divide 12x^4+17^3+8x-40 by x-2
chubhunter [2.5K]

Answer:

12x^3 + 24x^2 + 48x + 104 + (5081/x-2)

Step-by-step explanation:

12x^4 + 17* (17*17) + 8x -40/ x-2

1. remove the parenthesis

12x^4 + !7 * 17 * 17 + 8x -40 / x-2

2. multiply 17 by 17

12x^4 + 289 * 17 + 8x -= 40 /x-2

3. multiply 289 by 17

12x^ = 4913 + 8x - 40 / x-2

4. move 4913

12x^4 + 8x + 4913 - 40 / x-2

5. subtract 40 from 4913

12x^4 + 8x + 4873 / x-2

6. set up polynomials to be divided. if there is not a term for every exponent, insert one with a value of 0

x-2 into 12x^4 + 0x^3 + 0x^2 + 8x + 4873

7. divide the highest order term  in the dividend 12x^4 by the highest order term in divisor x = 12x^3

8. multiply by new quotient term

12x^3 * x-2 = 12x^4 -24x^3

9. the expression needs to be subtracted from the dividend, so change all the signs in 12x^4 - 24x^3

12x^4 + 0x^3 - 12x^4 + 24x^3

10. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

+24x^3

11.  pull the next term from the original dividend down into the current dividend

+24x^3 + 0x^2

12.  divide the highest order term in the dividend 24x^3 by the highest order term in divisor x = 24x^2

12x^3 + 24x^2

13. multiply new quotient by the divisor

24x^3 * x-2 = 24x^3 - 48x^2

14. the expression needs to be subtracted from the dividend, so change all the signs in 24x^3 - 48x^2

24x^3 + 0x^2 - 24x^3 + 48x^2

15. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

+48x^2

16. pull the next terms from the original dividend down to the current dividend

+ 48x^2 + 8x

17. divide the highest order term in the dividend 48x^2 by the highest order term in the divisor = 48x

12x^3 + 24x^2 + 48x

18. multiply the new quotient term by the divisor

48x * x - 2 = 48x^2 - 96x

19. the expression needs to be subtracted from the dividend, so change all the signs in 48x^2 - 96x

-48x^2 + 96x

20. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

48x^2 + 8x - 48x^2 + 96x

= 104x

21. pull the next terms from the original dividend down to the current dividend

+ 104x + 4873

22. divide the highest order term in the dividend 104x by the highest order term in the divisor x = 104

23. divide the new quotient by the divisor

104 * x -2 = 104x - 208

24. the expression needs to be subtracted from the dividend, so change all the signs in 104x - 208

104x + 4873 - 104x + 208 = 5081

25. the final answer is the quotient plus the remainder over the divisor

12x^3 + 24x^2 + 48x + 104 + (5081 / x - 2)

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