3 years ago

2 if x = 137,2° and sin(x-y) Determine the numerical value of: cos y.tanx y = 114,99

Mathematics

1 answer:

Amanda [17]3 years ago

3 0

Answer:

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Considere os logaritmos log3=0,477 , log4=0,602 e / log5=0.699 logaritmos determine o valor de log5 12.

anygoal [31]

Given that :

log3=0.477 , log4=0.602 and log5=0.699

Now , as you know that

$\log\text{MN}=\log M +\log N$

We have to find the value of

$\log_{5}12$

So, $\log_{5}12$ = $\frac{\log12}{ \log5}$

= $\frac{\log 4+\log 3}{\log 5}\\$

Now Putting the values of log3, log4 and log5 in the above expression

$\log_{5}12=\frac{0.477 +0.602}{0.699}$

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Find k given that these three points are collinear. A(0, -2), B(2, 0), and C(5, k)

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Step-by-step explanation:

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2 if x = 137,2° and sin(x-y) Determine the numerical value of: cos y.tanx y = 114,99​

2 if x = 137,2° and sin(x-y) Determine the numerical value of: cos y.tanx y = 114,99