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Assoli18 [71]
3 years ago
8

The table shows the price of movie tickets as a function of the number of tickets.

Mathematics
1 answer:
GaryK [48]3 years ago
5 0

Answer: d

Step-by-step explanation:

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Gary wanted to determine the average height of boys at the high school. His older brother is on the basketball team, so he asked
fomenos

Answer:

The answer would be "no because boys on the basketball team are likely to be taller than other boys at the school"

Step-by-step explanation:

Hope this helps:)...if not then sorry for wasting your time and may God bless you:)

5 0
2 years ago
Write an iequality for -5(×+7)<-10 representing the solution for x​
vovikov84 [41]

Answer:

X<-5

Step-by-step explanation:

1) open the brackets

2) take -35 to the other side with -10

where it turns to be -5X<-10+35

3) work out to find -5X<25

4) divide both sides by -5

to find X<-5

3 0
3 years ago
A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c
olchik [2.2K]
The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in E^{c}. Find P(E^{c}).

Solution:

Part 1:

E^{c} means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

E^{c}=S-E \\  \\ &#10;E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\  \\ &#10;E^{c}=(4,5,6)

Thus the set compliment of E will contain the elements {4,5,6}.So

E^{c} = {4,5,6}

Part 2)

P(E^{c}) means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

P(E^{c}) = (Number of Elements in E^{c})/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set E^{c} = n(E^{c})=3

So, 

P(E^{c})= \frac{n(E^{c}) }{n(S)} \\  \\ &#10;P(E^{c})= \frac{3}{12} \\  \\ &#10;P(E^{c})= \frac{1}{4}
7 0
3 years ago
Please help me to answer these questions!! Thank you in advance.
oksano4ka [1.4K]
1. 
5u - 2u = 3u (diff. between longest and shortest)
3u = 87cm
1u = 87cm ÷ 3 = 29cm
5u + 4u + 2u=11u
11u = 11 x 29cm = 319cm

Ans: 319cm

2.
9u = 1350
1u = 1350 ÷ 9 = 150
6u + 5u = 11u
11u = 11 x 150 = 1650

Ans: 1650


8 0
3 years ago
Mike makes and sells skateboards. If he has a cost of $6,200 per year plus a cost of $15 per skateboard, how many skateboards mu
Roman55 [17]

Answer: 310

Step-by-step explanation:

35-15= 20

6200 / 20 = 310

3 0
2 years ago
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