Answer:
a)2.46 %
b)For 1 :101.52 %
For 2 : 99.08 %
c)100..4 %
Explanation:
Given that
g₁ = 9.96 m/s²
g₂ = 9.72 m/s²
The actual value of g = 9.8 m/s²
a)
The difference Δ g = 9.96 -9.72 =0.24 m/s²
b)
For first one :
For second :
c)
The mean g(mean )
a)2.46 %
b)For 1 :101.52 %
For 2 : 99.08 %
c)100..4 %
Answer:
The force of the air on the skydiver's body is:
Explanation:
Let's recall that when an object reached terminal velocity, the force of the air acting is equal to the weight of the object, so the net force will be zero, that is why the object falls at a constant speed.
Then we have:
where:
m is the mass of the skydiver (65 kg)
g is the gravity acceleration (9.81 m/s²)
Therefore, the force of the air on the skydiver's body is:
I hope it helps you!
<span>Using the kinematic equation:
(final speed)^2 = (initial speed)^2 + 2 * acceleration * distance
(12)^2 = (0)^2 + 2 * acceleration * distance
The child and sled are accelerating under gravity which exerts a force down the hill, so acceleration = g = 9.8 m/s^2 in the "down" direction.
144 = 2 * 9.8 * "down" distance (height of the hill)
height of the hill = 7.35m</span>