Answer:
NE DIYON INGILIZ MISIN SEN
The initial speed of the shot is 15.02 m/s.
The Shot put is released at a height y<em> </em>from the ground with a speed u. It is released at an angle θ to the horizontal. In a time t, the shot put travels a distance <em>R</em> horizontally.
Pl refer to the attached diagram.
Resolve the velocity u into horizontal and vertical components, u ₓ=ucosθ and uy=u sinθ. The horizontal component remains constant in the absence of air resistance, while the vertical component varies due to the action of the gravitational force.
Write an expression for R.

Therefore,

In the time t, the net displacement of the shotput is y in the downward direction.
Use the equation of motion,

Substitute the value of t from equation (1).

Substitute -2.10 m for y, 24.77 m for R and 38.0° for θ and solve for u.

The shot put was thrown with a speed 15.02 m/s.
To help pick to up the metal and place it in a incinerator <span />
Answer:

Explanation:
The relative velocity can be calculated by means of the difference between vector B minus vector A.

Answer:
Option C
Explanation:
When this type of situation occurs where the price falls and the sale of a product increases then a shift is observed in the supply curve towards right as a result of this shift there is a need to shift down the demand curve
Thus When supply curve is shifted to the right the demand curve is moved down accordingly.