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Nookie1986 [14]
3 years ago
12

A rectangular field is 300 meters long and 300 meters wide. What is the area of the field in square kilometers? Do not round you

r answer. Be sure to include the correct unit in your answer.
Physics
1 answer:
dexar [7]3 years ago
6 0

Answer:

Area of the rectangular field in kilometers is 0.09 km^2

Explanation:

We know that 1 kilometers = 1000 meters

                    since we need to find the area in unit of kilometers

                    therefore converting length and width into kilometers

           1000 meters = 1 kilometers

             300 meters =\frac{300}{1000} = 0.3

         Likewise  width  = 0.3 km

Area = length x width

         = 0.3km x 0.3 km

        = 0.09 km^2

       

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A car with mass 950 kg and a speed of 16 m/s approaches an intersection. A 1300 kg minivan traveling at 21 m/s is heading for th
Alex73 [517]

Answer:

V_f = 13.8863 \angle 60.89\°

Explanation:

Our values are,

m_1 = 950Kg\\v_1 = 16m/s \\m_2 =1300Kg\\v_2 = 21m/s

We have all the values to apply the law of linear momentum, however, it is necessary to define the two lines in which the study will be carried out. Being an intersection the vehicle of mass m_1 approaches through the X axis, while the vehicle of mass m_2 approaches by the y axis. In the collision equation on the X axis, we despise the velocity of object 2, since it does not come in this direction.

m_1v_1=(m_1+m_2)v_fcos\theta

For the particular case on the Y axis, we do the same with the speed of object 1.

m_2v_2=(m_1+m_2)v_fsin\theta

By taking a final velocity as a component, we can obtain the angle between the two by relating the equations through the tangent

Tan\theta = \frac{m_2v_2}{m_1v_1}\\Tan\theta = \frac{1300*21}{950*16}\\\theta = tan^{-1}(1.7960)\\\theta = 60.89\°

Replacing in any of the two functions, given above, we will find the final speed after the collision,

(950)(16)=(950+1300)V_fcos(60.89)

V_f= \frac{(950)(16)}{(950+1300)cos(60.89)}

V_f = 13.8863 \angle 60.89\°

8 0
3 years ago
In a two planet system, does an increase in planet velocity result in a decreased period?
olganol [36]
From the formula,
                                 v=2πr/T
V(velocity is inversely related to T),so when v increases then time period will decrease.
Option a is correct.
5 0
3 years ago
Read 2 more answers
A 100-newton box is placed on a table. The table can exert a maximum normal force of 80 newtons. What will happen to the box?
myrzilka [38]

Answer:

D

Explanation:

Dddddddddddddddddd

8 0
3 years ago
A person stands on the ball of one foot. The normal force due to the ground pushing up on the ball of the foot has magnitude 750
White raven [17]

Answer:

the force exerted on the foot by the tibia would be 2975 N

Explanation:

Given the data in the question;

To maintain equilibrium between the foot and the ball vertically, the addition normal normal force N^> (750 N)  and the tension in the Achilles tendon F^>_{Achilles} (2225 N) must be equal to the force exerted on the foot by the tibia;

so

| N^> | + |F^>_{Achilles} | = | F^>_{Tibia} |

so force exerted on the foot by the tibia will be;

| F^>_{Tibia} | = |N^> | + |F^>_{Achilles} |

so we substitute IN OUR VALUES

| F^>_{Tibia} | = 750 N + 2225 N

| F^>_{Tibia} |  = 2975 N

Therefore, the force exerted on the foot by the tibia would be 2975 N

3 0
3 years ago
Blown balloon kept outside on a sunny day bursts what will happen to the ballon​
Advocard [28]

When the balloon is kept in the sun, due to Sun's heat, the kinetic energy of gaseous particles inside the balloons also gets increased and the balloon expands. This will increase the pressure on the walls of the balloon. It continues to expand and comes to a stage when the baloon bursts.

5 0
3 years ago
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