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denis-greek [22]
3 years ago
15

A researcher is 95% confident that the interval from 2.9 minutes to 6.83 minutes captures u = the true mean amount

Mathematics
2 answers:
Sholpan [36]3 years ago
7 0

Answer:

Answer is d.

Step-by-step explanation:

edg 2020

chubhunter [2.5K]3 years ago
7 0

Answer:

D. Yes, this is plausible for the population mean because the upper boundary of the 95% confidence interval is below 7 minutes.

Step-by-step explanation:

You might be interested in
The sales tax for an item was $16.40 and it cost $410 before tax.
emmasim [6.3K]

Answer:

4%

Step-by-step explanation:

410 plus 16.4 is 426.4 take away 16.4 then you got 410 it is 410+4%=426.4

8 0
3 years ago
PLEASE HELPP!! RIGHT ANSWERS WILL GET BRAINLIEST!!!
Alecsey [184]

Answer:

4

Step-by-step explanation:

8 0
3 years ago
Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturd
mestny [16]

Answer:

1) P(X = 8) = 0.1033

P(X = 9) = 0.0688

2) Expected number of 200 restaurants in which exactly 8 customers use the drive-through: 20.66

Expected number of 200 restaurants in which exactly 9 customers use the drive-through: 13.76

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Question 1. Use the Poisson distribution to calculate the probability that exactly 8 cars will use the drive-through between 12:00 midnight and 12:30 AM on a Saturday night at Wendy's. Do the same for exactly 9 cars.

Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturday nights. This means that during 30 minutes, 6 cars expected to arrive. So \mu = 6.

P(X = 8)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 8) = \frac{e^{-6}*(6)^{8}}{(8)!} = 0.1033

P(X = 9)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 9) = \frac{e^{-6}*(6)^{9}}{(9)!} = 0.0688

Question 2. At how many of the 200 restaurants in the survey would you expect exactly 8 customers to use the drive-through? exactly 9 customers?

There is a 10.33 probability that 8 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.1033 = 20.66

There is a 6.88 probability that 9 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.0688 = 13.76

8 0
3 years ago
Pls anyone can help?
Luba_88 [7]
I think it’s 9/10 mile
3 0
3 years ago
Write the numerical expression 34 in expanded form.
garik1379 [7]

Answer:

not sure what type you mean but here are options

Step-by-step explanation:

30+4=34

thirty-four

5 0
2 years ago
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