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vodka [1.7K]
4 years ago
8

Please help will mark Brainly

Mathematics
2 answers:
castortr0y [4]4 years ago
6 0

The answer would be C

VLD [36.1K]4 years ago
4 0
The answer is C cause it is already at 24 then the 6.5 rain per day adds to it so y=6.5x
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Michelle is making throw pillows to decorate her couch. She is going to make two square pillows that are each 2 feet by 2 feet a
lesantik [10]

ok so for the 2 ft pillows the perimeter would be 8 ft and for the 1 ft pillows the perimeter would be 3 ft. So you would need 8(2)+3(3)=16+9=25 so she needs 25 feet of trimming.

3 0
4 years ago
Please help with this question
Semenov [28]

Answer:

Line BC

Step-by-step explanation:

Opposite means whatever is exactly parallel to angle a.

In this case, we notice BC to satisfy that rule.

Hope this helps.

Good Luck

5 0
4 years ago
Read 2 more answers
A company makes wax candles in the shape of a cylinder. Each candle has a diameter of 8 inches and a height of 3 inches. How muc
Sveta_85 [38]

Answer:

18,086.4 cubic units

Step-by-step explanation:

The volume of one such cylinder can be computed by multiplying the height by pi by the radius squared: 3×3.14×4²=150.72.

If you want to make 120 candles, multiply that number by 120: 150.72×120=18086.4.

3 0
3 years ago
Match its group with its percentage or mean Using
krok68 [10]

(1)

Mean length of all fish in the sample - \boxed{\sf{\red{6.2}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

=<em> 6.2</em>

(2)

Mean length of adult fish in the sample - \boxed{\sf{\red{8.75}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

=<em> 8.75</em>

(3)

Mean length of juvenile fish in the sample - \boxed{\sf{\red{4.5}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

<em>= 4.5</em>

(4)

Percentage of sample that were adult fish - \boxed{\sf{\red{40}}}

<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

<em>% = 40</em>

(5)

Percentage of sample that were juvenile fish - \boxed{\sf{\red{60}}}

<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

<em>% = </em><em>6</em><em>0</em>

(6)

Percentage of sample that were juveniles over 8 inches long - \boxed{\sf{\red{10}}}

<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

<em>% = </em><em>1</em><em>0</em>

7 0
3 years ago
Can someone plz help me answer the hole question
stiks02 [169]

Answer:

He needs one more quart

Step-by-step explanation:

4 0
3 years ago
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